Find the regression equation (rounding values to 2 places), letting the first variable be the independent variable x. Use the regression equation values to find the best predicted gross amount for a movie with a budget of 69 million dollars. Hint: Use the exact regression values to find an accurate predicted value and then round your answer. In the table below, all amounts are in millions of dollars.   Budget 95 195 80 89 92 92 86 83   Gross 60 599 57 47 66 65 55 62   y = ? +?  x y69 =?

For the data in the table, find the regression equation and then use it to answer the questions below. Here, x gives a student's annual family income (in $1000's), and y is the student's SAT score. Round the slope and y-intercept to two decimals, then do not round your answer. Income SAT ($1000's) Score 62 940 66 950 75 960 77 980 78 990 79 1010 82 1020 86 1080 90 1090 100 1100 a. What is the predicted score for a student whose annual family income is $115,000? b. Is your answer to part (a) an extrapolation? O No: the value of x is within the range of the data, so the prediction is meaningful O Yes: the value of x is outside the range of data, so the prediction may not be meaningful

The data show the chest size and weight of several bears. Find the regression​ equation, letting chest size be the independent​ (x) variable. Then find the best predicted weight of a bear with a chest size of 48 inches. Is the result close to the actual weight of 538 ​pounds? Use a significance level of 0.05.

2. The table below lists the annual land-line phone cost per costumer: Year 2012 2013 2014 2015 Cost ($) a. 692 610 Find a linear regression model for this data b. Interpret the slope of the model 580 C. Predict the annual land-line phone cost per customer in 2022 495 2016 434

Find the regression line (even if there isn't correlation in the population) Write the meaning of the slope of the regression line: Find the best predicted score a wife would have, if her husband scored 50:

Is the following table created with an exponential or a linear equation? Y 1 10 13 3 16 4 19

The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 63 inches. Is the result close to the actual weight of 442 pounds? Use a significance level of 0.05. Chest size (inches) 58 50 65 59 59 48 Weight (pounds) 414 312 499 450 456 260 Click the icon to view the critical values of the Pearson correlation coefficient r. What is the regression equation? Critical Values of the Pearson Correlation Coefficient r y=D+x (Round to one decimal place as ne Critical Values of the Pearson Correlation Coefficient r NOTE: To test Ho: p=0 against H,: p+0, reject Ho if the absolute value of r is greater than the critical value in the table. a = 0.05 a = 0.01 4 0.950 0.990 0.878 0.811 0.754 5 0.959 6 0.917 7 0.875 8 0.707 0.834 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482…

A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a person can do (y). The results of the regression were: y=a+bx b=-0.66 a=25.376 r²=0.390625 r=-0.625 Use this to predict the number of situps a person who watches 2.5 hours of TV can do. place. Round to one decimal

What is the dollar amount of change in sales for each new year according to the regression (slope) model?  Do not use commas or $ in your answer.

The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 40 inches. Is the result close to the actual weight of 352 pounds? Use a significance level of 0.05. Chest size (inches) *Weight (pounds) 44 54 328 528 41 55 39 51 418 580 296 503 Click the icon to view the critical values of the Pearson correlation coefficient r. - What is the regression equation? x (Round to one decimal place as needed.)