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Find the position vector for a particle with acceleration, initial velocity, and initial position given below. d(t) = (4t, 5 sin(t), cos(5t)) v(0) = ( – 1, 1, – 4) 7(0) = (– 5, 2, 2) 7(t) =

Find the position vector for a particle with acceleration, initial velocity, and initial position given below. d(t) = (4t, 5 sin(t), cos(5t)) v(0) = ( – 1, 1, – 4) 7(0) = (– 5, 2, 2) 7(t) =

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the position vector for a particle with acceleration, initial velocity, and initial position given below. a(t) = (4t, 5 sin(t), cos(5t)) i(0) = (– 1, 1, – 4) - 7(0) = (– 5, 2, 2) F(t) =
Transcribed Image Text:Find the position vector for a particle with acceleration, initial velocity, and initial position given below. a(t) = (4t, 5 sin(t), cos(5t)) i(0) = (– 1, 1, – 4) - 7(0) = (– 5, 2, 2) F(t) =
Let 7 (t) = < 3t? + 1, t? + 3t°, – 3 In(3t) > Find a parametric equation of the line tangent to r(t) at the point (28, 738, – 6.592) x(t) = 28 + 18t %3D y(t) 738 + syntax error. z(t) -6.592 + syntax error.
Transcribed Image Text:Let 7 (t) = < 3t? + 1, t? + 3t°, – 3 In(3t) > Find a parametric equation of the line tangent to r(t) at the point (28, 738, – 6.592) x(t) = 28 + 18t %3D y(t) 738 + syntax error. z(t) -6.592 + syntax error.
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