Find the P-value for the indicated hypothesis test. A nationwide study of American homeowners revealed that 65% have one or more lawn mowers. A lawn equipment manufacturer, located in Omaha, feels the estimate is too low for households in Omaha. Find the P-value for a test to support the claim that the proportion with lawn mowers in Omaha is higher than 65%. Among 497 randomly selected homes in Omaha, 340 had one or more lawn mowers. 0.0559 O 0.0252 O 0.1118 O 0.0505

In the Texas senate races, a candidate must clear 50% to avoid a runoff election. In a recent poll of 1040 voters in Texas, 51% of voters preferred candidate. We will a hypothesis test to see if we can say at the 5% significance level that more than 50% of voters in Texas prefer candidate based on this poll. State the null and alternative hypothesis. Find the test-statistic. Find the P-value. Make a conclusion. Interpret your answer.

Construct a 95% confidence interval for p1 - p2 for a survey that finds 30% of 240 males and 41% of 200 females are opposed to the death penalty. Group of answer choices a.(-0.200, -0.021) b.(-1.532, 1.342) c.(-1.324, 1.512) d.(-0.561, 0.651)

Portland State University (PSU) reported that 64% of their students receive financial aid. A PSU administrator feels that their school may have a different proportion compared to all of Oregon schools. A random sample of 409 students in Oregon found that 259 receive financial aid. Test the claim that proportion of students that receive financial aid in Oregon is different than PSU. Use a 1% significance level. Give answer to at least 4 decimal places. a. What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.) Ho: Select an answer ?v H₁: Select an answer ? ✓ Based on the hypotheses, compute the following: b. Test Statistic = c. p-value = d. Based on the above we choose to Select an answer e. The correct summary would be: Select an answer that the proportion of students that receive financial aid in Oregon is different than the PSU reported value of 64%.