Find the optimal solution for the following problem. (Round your answers to 3 decimal places.) Maximize C = subject to and 18x + 23y + 10z 14x + 16y + 23z ≤ 56 9x + 8y + 7z ≤ 112 x 28, y 28, z 20. a. What is the optimal value of x? b. What is the optimal value of y? c. What is the optimal value of z? d. What is the maximum value of the objective function? Maximum value

Minimize. w = 2y1 + 4y2 Subject to: 4y1 + 2y2 2 10 4y1 + y2 > 8 2y1 + y2 > 12 У1 2 0, Y2 2 0 ***Note: Notice in the constrains, the second inequality is a multiple of the last inequality. So if we multiply last inequality by 2, I would get the same terms that exist to left hand side of inequality as in equation 2. Therefore, we have dependency. When this happens, you only need one of these as using both is redundant. Because of this, assume the second inequality in the constraints is not there and solve using first and last inequality.

Use the information below to answer question  2x + 3y + 3z = 2 4x – 3y – 6z = 2 10x – 6y + 3z = 0 1. Given values – 144, -192, and 96 for Dx, Dy, and Dz respectively and D = 144. Then the solution to the system        for x, y and z are: A. -1, -1.33, and 0.67 B. -0.47, -0.63 and 0,30 C. 0.5, 0.67 and-0.33 D. 0.73, 0.98 and -0.49

Please answer the dotted green question. Thank you