Find the minimum diameter of an I = 15.4 m long brass wire that will stretch no more than 7.83 mm when a mass of 335 kg is hung on the lower end. (Hint: The Young's modulus of brass is 91.0 GPa.)
Q: Common sports injuries result in the tearing of tendons and ligaments due to overstretching. If the…
A:
Q: A wire having Young's modulus 1.2 × 10¹1 N/m² is subjected to the stress of 2.4 × 10¹ N/m². If the…
A: Given :- Young's modulus Y = 1.2*1011 N/m2 stress σ = 2.4 × 107 N/m². length l = 10m
Q: The unknown metal cube measures 4.2 x 10 ― 2 m has a stress of 9.2 x 1011 N/m 2 and a change of…
A:
Q: A steel wire of length 4.7 m and cross-sectional area 3.0 × 10-5 m2stretches by the same amount as a…
A:
Q: Find the Young’s modulus of the wire. (g= 9.81 m/s/s)
A:
Q: The Young’s modulus for steel is at most 215 GPa (1 GPa= 109 N/m2). If you apply a force of 50.0…
A: Given quantities: Young's modulus of steel (Y) = 215 GPa Applied force (F) = 50 GPa initial length…
Q: Find the minimum diameter of an | = 15.1 m long tungsten wire that will stretch no more than 7.00 mm…
A:
Q: On a forest trail a 4m long birch tree trunk is laid across a ravine as a bridge. The trunk is 4m…
A: Given that, The length of the trunk = 4 mThe diameter of the trunk = 20 cmThe Young's modulus of…
Q: A brass wire with Young’s modulus of 92.0 GPa is 1.95 m long and has a cross-sectional area of 5.00…
A: The objective of the question is to find out how much a brass wire stretches when a certain weight…
Q: A 4.0-m-long steel wire has a cross-sectional area of 0.050 cm². Its proportional limit has a value…
A: We know, The steel wire has a length of 4 m and a cross sectional area of 0.050 cm2. Its stress is…
Q: If the elastic limit of copper is 1.50 x 108 N/m2, determine the minimum diameter a copper wire can…
A: Given- If the elastic limit of copper is 1.50 x 108 N/m2, determine the minimum diameter a copper…
Q: A 50.0 kg object is hung from the end of a wire of cross-sectional diameter of 1.12 mm. The wire…
A: Given: m=50kg d=1.12mm r=0.56×10-3m l=200cm=200×10-2m=2m ∆l=0.5cm=0.5×10-2m
Q: A 92.1-kg man’s thighbone has a relaxed length of 0.762 m, a cross-sectional area of 7.00 × 10−4 m2,…
A: The objective of this question is to find out how much the thighbone of a man compresses when he is…
Q: A uniform metal bar, one metre long, is placed symmetrically on two knife-edges separated by a…
A: We can use the formula for the deflection of a uniformly loaded beam supported at its ends: δ =…
Q: A copper wire of length 6.1 m, cross sectional area 1.7 7 * 10^-6 * m^2 Young's modulus 11 * 10^10…
A: Given data: Length (L) = 6.1 m Cross-sectional area (A) = 1.77×10-6 m2 Young's modulus (Y) = 11×1010…
Q: A control rod made of yellow brass must not stretch more than 3 mm when the tension in the wire is 4…
A: Solution:-Given thatDeformation in control rod (δ)=3 mmTension in the wire (T)=4 kN=4×103 NYoung's…
Q: TTM i. Figure 4 shows a 12 kg weight suspended by a 0.3 m vertical copper wire with cross sectional…
A: Concept: In order to calculate the Strain in each of the wire we will firstly calculate the stress…
Q: A 2 m long steel rod has a cross-sectional area of 0.3 cm?. The rod is a part of a vertical support…
A: The stress of the rod is given by F/A Strain is given by dL/L where F= Force…
Q: If a 6.0 x 10^3 mm elastic cable of density 1.1 x 10^3 kg/m^3 is dangling, how much does the length…
A:
Q: A wire of uniform cross sectional area of 0.45 mm is stretched at both ends by a total force of 7O N…
A: Given: Area of cross section of wire is 0.45 mm2. Force acting on the wire is 70 N. Strain produced…
Q: A copper wire of length 7.9 m, cross sectional area 2 x 10 m²and Young's modulus 11 x 1010 N/m has a…
A:
Q: A member is formed by connecting two steel bars shown below. Assuming that the bars are prevented…
A:
Q: A copper wire of length 8.7 m , cross sectional area 1.3 x 10-6m2and Young’s modulus 11 x 1010 N/m2…
A:
Q: A marble column with a cross-sectional area of (2.70x10^1) cm² supports a load of (5.500x10^4) N.…
A:
Q: A bob of mass 30 kg hangs from a copper wire ( Y= 11x10 ^10 N/m^2). The wire has an initial length…
A:
Q: A steel wire having a radius of 2.0 mm, carrying a load of 4 kg, is hanging from a ceiling. Given…
A: Given that, Radius of wire, r=2 mm=2×10-3 m, Weight of load, m=4 kg, g=3.1π ms-2
Q: A 92.0-kg man’s thighbone has a relaxed length of 0.789 m, a cross-sectional area of 7.00 × 10−4 m2,…
A: The objective of the question is to find out how much the thighbone of a 92.0-kg man compresses when…
Q: Problem 12: Consider the effect of wires hung on poles in which the left wire made an angle 29°…
A:
Q: A 350 mm diameter solid steel drive shaft transmits 4500 kW at 120 rpm to a hollow steel shaft via a…
A: Given,Drive shaft diameter (D) = 350 mm Transmitted power (P) = 4500 kW Rotational speed (N) = 120…
Q: A 28.0 m long aluminum cable with a cross-sectional area of 2.01 ✕ 10−3 m2 is used to suspend a 3.40…
A: Y=mg/A∆L/L =mgLA∆L∆L=mgLYA
Q: A steel wire having a radius of 2.0 mm, carrying a load of 4kg, is hanging from a ceiling. Given…
A:
Q: An elevator is suspended by a steel cable of diameter 2.5cm. The steel has an ultimate tensile…
A: Given, Diameter =2.5 cm Ultimate tensile strength is 860Mpa Let T denote tension in the cable and a…
Q: The legs of a weight lifter must ultimately support the weights he has lifted. A human tibia…
A: Given data- For human tibia (shinbone) outer diameter Dout=3.6 cm=0.036 m inner diameter Din=2.5…
Q: Ropes for rock climbing have a diameter of 10.5 mm and a Young's modulus of 8.72x107 N/m². If a rock…
A: A material's ability to withstand length changes under longitudinal tension or compression is…
Q: A sphere of copper has a radius of 8.00 cm and is compressed uniformly by a force of 5.00 × 108 N.…
A:
Q: Assuming that the youngs modulus of spider ilk is 8.4x10^9 pascals. If the spider silk a radius of…
A:
Q: Four wires of the same material are stretched by the same load. Which one of them will elongate the…
A: To find-Which wire will elongate more=?Given-Dimensions of different wires are as follows.(a) l=50…
Trending now
This is a popular solution!
Step by step
Solved in 2 steps