Find the magnitude of the net resultant force. Given: F1=328 N F2= 219 N e=0.75 rad ф-25° Answer: X N F2 53 46 F1
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Q: 2. A 50.0kg marathon runner runs up the stairs to the top of a 443m tall tower. To lift herself to…
A: Given Mass m = 50 kg Displacement S= 443 m Time taken= t = 15 min = 15 × 60 = 900 second
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Q: Determine the resultant of the force system in the figure. y 450N, 850 N 48° 5 350 N 55 500N
A: To find the resultant force, we will first find components of given forces along x and y directions.…
Q: 12:34 PM A Vectors report (1).pdf Exercise: Using both the component method and the graphical method…
A: Dear student The resultant of two vectors can be found by adding them in vector form. For that we…
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Q: Fi3 7 37.0° F2, Compute for the total force exered on q2 . 4.00m 92 93 to but 3.0om 1 5-00m メ q2…
A: Given Charges are q1=1 Cq2=-2 Cq3=3 C Distance between the charge 3 and the charge 1 is r21=3.00…
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A: Solution:Resolving the given forces into horizontal and vertical components we have:…
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Q: The 100 lb force is exerted on A to the left. Determine the ma along members AB and AC. 100 lb A 40⁰…
A: We need to convert member forces into components.
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A: Step 1:Step 2: Step 3: Step 4:
Q: Problem 5 An 18-N weight is held by two strings, as show. What are both tensions T₁ and T₂?
A: Weight=18 Nvalues of T1 and. T2values of T1 and. T2
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A: Given, θ=24.040β=33.610F=142.42Q=61.43P=113.54
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Q: Answers: Fx= Fy= Fn = Ft= i i i 67° 47° B F = 850 lb lb lb lb lb
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Q: Given the following data calculate the sum of the FQ and FP VERTICAL force components. NOTE if your…
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Q: 3) Two cables are attached to the pole as shown below. Find the following: 15°T 800 lb 900 lb a. The…
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A: Fx=-400kNFy=150 kNFA=(-400)2+1502=427.20kNθ=tan-1150-400=-20.6°Since vector is in second quadrant…
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Q: F1= 10 + A (kN) 40° F2= 20 + B (kN) 13 12 20 + C (degrees) F,= 36 kN Determine the horizontal…
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Q: F₂ = 600 N 45° F₁ = 800 N ·X F3 = 650 N 60°
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Q: 3–6. Determine the force in member C and its angle 0 for equilibrium. The forces are concurrent at…
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Q: What is the magnitude of the net Force (F= F₁+F2) measured in N? F₂=18N 50 y 30 F=30N X
A: Given F1=30 N F2=18 N Required Magnitude of net force F1+F2
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A: Given data: The magnitude of force F=100 N. Angle with the axis θ=30∘.
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A: Draw the free body diagram.
Q: y F1 = 30 N %3D 3 4 F3 = 50 N 20° F2 = 20 N
A: →F1 = 30 ((-4/5) i^+ (3/5)j^) →F1 = -24i^ + 18j^→F2 = 20 ((-sin20o) i^- (Cos20o)j^) →F2 = -6.84i^ -…
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A: Detailed solution is given below:
Q: Problem 05: Determine the resultant of the three non-concurrent forces shown. Locate its…
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