College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- Suppose you walk 18.0 m straight west and then 25.0 m straight north. How far (in meters) are you from your starting point?arrow_forwardA driver takes a wrong turn at an intersection and travels 2.6 km north, then 8.7 km east and finally 7.5 km south. What is his displacement from the intersection? Enter your answers without units, correct to three significant digits. (a) The magnitude of the displacement is: This question accepts numbers or formulas. Help | Switch to Equation Editor | Preview (b) The direction of the displacement is: Enter your answer in standard position as an angle in degrees such that 0º < 0< 360°arrow_forwardThe car travels around the circular track having a radius of r = 300 m such that when it is at point A it has a velocity of 8 m/s, which is increasing at the rate of v = (0.08t) m/s², where t is in seconds. (Figure 1) Figure A X 1 of 1 Part A Determine the magnitude of the velocity when it has traveled one-third the way around the track. Express your answer to three significant figures and include the appropriate units. V = Submit Part B Value a = μA 0 Submit Request Answer Determine the magnitude of the acceleration when it has traveled one-third the way around the track. Express your answer to three significant figures and include the appropriate units. O μÀ Value Units Request Answer ? Units ?arrow_forward
- Find the magnitude of the instantaneous acceleration (in m/s²) of an object that moves at a constant speed around a circle if it take it 4.24 s to complete one revolution. The radius of the circle is 2.52 m.arrow_forwardA car is driven 230 km west and then 85 km southwest. What is the magnitude of the car's displacement?arrow_forwardanswer with steps pleasearrow_forward
- D = (oxt) + (1/2 * 8.93* (4.7)2) I D = 98.63 meter 5. You are about to skateboard down a long hill. Your initial velocity is 2.0 m/s south. When you reach the bottom of the hill you are travelling 6.0 m/s south. It took you 57 seconds to reach the bottom of the hill. What was your displacement?arrow_forwardThe velocity of an object is given by, = u + at V ds dt. where, u is the initial velocity, a is the acceleration, and ₺ is the time in seconds. Solve the differential equation to obtain the displacement, s, given that at t = 0, s = 7 (metres) : 1 if u = 3 ms ¹, a = 2.4 ms 2, calculate the displacements at t = 4.9 seconds. Give your answer to 2 decimal places.arrow_forwardThe position of an object in circular motion is modeled by the given parametric equations, where t is measured in seconds. x=7sin((pi/8)t), y=-7cos((pi/8)t) How long (in sec) does it take to complete one revolution?arrow_forward
- A child rides a pony on a circular track whose radius is 4.5 m.(a) Find the distance traveled and the displacement when the child has gone halfwayaround the track.(b) How does the distance traveled change while the child completes one circuit of thetrack? Explain.(c) How does the displacement change while the child completes one circuit of thetrack? Explain.(d) Find the distance and displacement after a complete circuit of the track.arrow_forwardneeds complete typed solution with 100 % accuracy.arrow_forwardThe acceleration due to gravity, g, is constant at sea level on the Earth's surface. However, the acceleration decreases as an object moves away from the Earth's surface due to the increase in distance from the center of the Earth. Derive an expression for the acceleration due to gravity at a distance h above the surface of the Earth, gh. Express the equation in terms of the radius R of the Earth, g, and h. &h= Suppose a 74.35 kg hiker has ascended to a height of 1893 m above sea level in the process of climbing Mt. Washington. By what percent has the hiker's weight changed from its value at sea level as a result of climbing to this elevation? Use g = 9.807 m/s² and R = 6.371 × 106 m. Enter your answer as a positive value. weight change = %arrow_forward
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