Find the instantaneous velocity of the particle described in the figure below at the x(m) 10 8- 6 4 (s) 1 4 6 -2 -4 t = 1.3 s m/s (a) t = 3.1 s m/s (b) t = 4.8 s m/s (c) (d) t = 7.1 s m/s

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Find the instantaneous velocity of the particle described in the figure below at the follow
x(m)
10
6.
4
2
(s)
4
6
-2
-4
(a)
t = 1.3 s
m/s
(b)
t = 3.1 s
m/s
(c) t = 4.8 s
m/s
(d)
t = 7.1 s
m/s
Transcribed Image Text:Find the instantaneous velocity of the particle described in the figure below at the follow x(m) 10 6. 4 2 (s) 4 6 -2 -4 (a) t = 1.3 s m/s (b) t = 3.1 s m/s (c) t = 4.8 s m/s (d) t = 7.1 s m/s
Expert Solution
Step 1

Given is position vs time Graph

Instantaneous velocity (v)= slope of position vs time graph  at that instant

                                          = dx/dt

(a) t= 1.3 s

    v = dx/dt

       =10/2 = 5 m/s

Slope is same for t=0  to t= 2 s

(b) t = 3.1 s

v = dx /dt = ∆x/∆t

 = (5-10)/(4-2)

  = -5/2 = - 2.5m/s

       

        

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