Find the first derivative of y = Arc tan √x² −1+ Arc csc x 2 O 2 O 0 2 Ox√²+1

Q: cos x y = %3D sin x + 1

A: Given,            y = cos xsin x + 1

Q: /4 tan x dx /4

A:

Q: 1) Find the derivative of y = e" tan x

A: As we know that; The chain rule; fgx'=f'gx·g'x And ddxex=exddxtanx=sec2x Given: y=etanx

Q: ] 1 1-x² dx = tan¹(x)

A:

Q: Find the following derivatives a. 2 tan-(2x²) b. e-3/5 -3/5 + 2x-3/4

A: Solving the problem by finding the derivative of the below function.

Q: The nth derivatives of sinªx is ㅎ4"cos(4x +

A: FALSE. SOLUTION IS GIVEN BELOW HANDWRITTEN DOCUMENT. nth derivative of sin^4x

Q: Subject 2/ Pind the derivatine o f the followiny 2x +tanx

A: Derivative of the function

Q: find the the Y = tanx( =

A:

Q: Find the 1st Derivative. r=( 2 tan3θ -1)1/3

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Q: 17. Find the first derivative for J(x)=tan0x sec0

A:

Q: What is the derivative of 0.50 sin 2t+0.30 cos t

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Q: cos(3x)dx

A: We’ll answer the first question since the exact one wasn’t specified. Please submit a new question…

Q: What are the derivatives of sin g(t), cos g(t), and tan g(t)?

A: we have to find the derivatives of sin g(t), cos g(t), and tan g(t)

Q: dx dx [sin(√2x³ + e)] [cos(√2π³ + e)]

A: The Power Rule:The Chain Rule:And use the common derivatives:

Q: b) Evaluate S e-2t sinht dt an

A:

Q: Step 2 Now write the derivative in terms of x by recalling that u = x³ = x + 8. [eu] = (eu) du dx…

A: I have solved step by step in detail....go through the solution

Q: Find the derivative of arc cos 4x.

A:

Q: [(csc 2x log tan x) + (sin 3x cos 3x)]dx

A: Given  The integration is ∫-π6π4csc(2xlog(tan x) +(sin 3x cos 3x)  dx