Answered: Find the equation of the line through the points (-1,-1) and (5,2) using point-slope form. Then rewrite the equation in slope-intercept form. y = 5-(-1)

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN: 9780134463216

Author: Robert F. Blitzer

Publisher: PEARSON

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Question

Find the equation of the line through the points (-1,-1) and (5,2) using point-slope form. Then
rewrite the equation in slope-intercept form.
y =
5-(-1)

Expert Solution

Given that the line passing through the points

$(- 1, - 1) & (5, 2)$ .

Equation of a line passing through the points $(x_{1}, y_{1}) & (x_{2}, y_{2})$ is,

$y - y_{1} = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1})$

Therefore equation of the line passing through the given points is,

$\Rightarrow y - (- 1) = \frac{2 - (- 1)}{5 - (- 1)} [x - (- 1)] \Rightarrow y + 1 = \frac{3}{6} (x + 1) \Rightarrow y + 1 = \frac{1}{2} (x + 1)$

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