Find the equation of an ellipse whose foci belong to the x-axis and passes through the points (4,3) (6,2)

The ellipse whose equation ise (x+2) , (y-3)² =14 4 9 can be parameterised by the equationse x=-2+9cost andy=3+4sinte A x=-2+3cost and y=3+2sinte x=2+9cost and y =-3+4sinte x=2+3cost and y =-3+2sinte E x=-2+3cost and y =-3+4sinte

Find the foci of the ellipse. 5x^2-20x+2y^2+12y=-28. The answers are 1. (-2+ square root of 3, 3) and (-2- square root of 3, 3) 2. (2+ square root of 3, -3) and (2- square root of 3, -3) 3. (2, -3+ square root of 3) and (2, -3- square root of 3) 4. (-2, 3+ square root of 3) and (-2, 3- square root of 3)

Write the equation of the hyperbola centered at the origin, with length of the horizontal transverse axis 6 and the curve passes through the point (7, -4).