Find the energy released in the alpha decay below: 21484Po 21082Pb + 42He You will find the following mass values useful. M(21484Po) = 214.023981 u M(21082Pb) = 210.014340 u M(42He) = 4.002602 u answer in MeV
Find the energy released in the alpha decay below: 21484Po 21082Pb + 42He You will find the following mass values useful. M(21484Po) = 214.023981 u M(21082Pb) = 210.014340 u M(42He) = 4.002602 u answer in MeV
College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter31: Radioactivity And Nuclear Physics
Section: Chapter Questions
Problem 79PE: (a) Write the decay equation for the decay of 235U. (b) What energy is released in this decay? The...
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Find the energy released in the alpha decay below:
21484Po 21082Pb + 42He
You will find the following mass values useful.
M(21484Po) | = | 214.023981 u |
M(21082Pb) | = | 210.014340 u |
M(42He) | = | 4.002602 u |
answer in MeV
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