Here, we need to find the derivative of f(x)=xx3+8.
So,
f'(x)=xx3+8' Apply the Quotient Rule: fg'=f '·g-g'·fg2. =x'x3+8-x3+8' xx3+82 =1·x3+8-3x22x3+8xx3+82 =-x3+162x3+8x3+8
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