Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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Question
4.1 #8
Title: Calculating the Derivative of a Given Function

**Objective:**
Find the derivative of the given function.

**Function:**
\[ y = \frac{-6}{2\sqrt{x}} \]

**Task:**
Calculate \(\frac{dy}{dx}\).

**Instructions:**
1. Simplify the function, if necessary.
2. Use the appropriate differentiation rules to find the derivative.

**Note:**
- \( \sqrt{x} \) can be rewritten as \( x^{1/2} \).
- Apply the power rule for differentiation, which states that \(\frac{d}{dx}(x^n) = nx^{n-1}\).

**Solution Steps:**
1. Rewrite the function: 
   \[ y = \frac{-6}{2} \cdot x^{-1/2} = -3x^{-1/2} \]
2. Differentiate using the power rule:
   \[ \frac{dy}{dx} = -3 \cdot \left(-\frac{1}{2}\right) x^{-3/2} \]
3. Simplify:
   \[ \frac{dy}{dx} = \frac{3}{2} x^{-3/2} \]

**Conclusion:**
The derivative of the function is:
\[ \frac{dy}{dx} = \frac{3}{2} x^{-3/2} \]
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Transcribed Image Text:Title: Calculating the Derivative of a Given Function **Objective:** Find the derivative of the given function. **Function:** \[ y = \frac{-6}{2\sqrt{x}} \] **Task:** Calculate \(\frac{dy}{dx}\). **Instructions:** 1. Simplify the function, if necessary. 2. Use the appropriate differentiation rules to find the derivative. **Note:** - \( \sqrt{x} \) can be rewritten as \( x^{1/2} \). - Apply the power rule for differentiation, which states that \(\frac{d}{dx}(x^n) = nx^{n-1}\). **Solution Steps:** 1. Rewrite the function: \[ y = \frac{-6}{2} \cdot x^{-1/2} = -3x^{-1/2} \] 2. Differentiate using the power rule: \[ \frac{dy}{dx} = -3 \cdot \left(-\frac{1}{2}\right) x^{-3/2} \] 3. Simplify: \[ \frac{dy}{dx} = \frac{3}{2} x^{-3/2} \] **Conclusion:** The derivative of the function is: \[ \frac{dy}{dx} = \frac{3}{2} x^{-3/2} \]
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