Find the derivative of the function. 1 In(1 + 49x 14 y = x arctan 7x dy

$$\begin{gathered} Given \\ y = x{\tan }^{-1}\left(7x\right) -\frac{1}{14}\ln (1+49x^2) \\ \frac{dy}{dx} = \frac{d\left( x{\tan }^{-1}\left(7x\right) -\frac{1}{14}\ln (1+49x^2)\right)}{dx} \\ \frac{dy}{dx} = \frac{d\left(x{\tan }^{-1}\left(7x\right)\right)}{dx}-\frac{1}{14}\frac{d(\ln (1+49x^2))}{dx} \end{gathered}$$