MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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How to find critical values of Z that corresponds to an 82% confidence level
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- Find the critical valuez Subscript alpha divided by zα/2that corresponds to the confidence level85%.arrow_forwardhelp pleasee thank you! A national organization sets out to investigate the change in prevalence of HIV since the last census in 2010. A total of 100 participants were interviewed and HIV prevalence in the sample is 7.5%. Assume that the data from the 2010 census indicated that the prevalence of HIV in the particular population was 5%. In order to test whether the prevalence of HIV now is significantly different from the HIV prevalence in 2010 at 95% confidence level, can we use a z-test to conduct a hypothesis test? Why? Why not? Group of answer choices Yes, we cannot use a z-test since ??0?0 = 100*0.075*(1-0.075)=6.93 > 5 Yes, we can use a z-test since ??0?0 = 100*0.05*(1-0.05)=4.75 < 5 Yes, we can use a z-test since ??0?0 = 100*0.075*(1-0.075)=6.93 > 5 No, we cannot use a z-test since ??0?0 = 100*0.05*(1-0.05)=4.75 < 5arrow_forwardAn article included data from a survey of a random sample of adults living in the United States. Of the 1,300 people who participated in the survey, 700 responded they believe that global climate change is a major threat to the well-being of the United States. USE SALT Use the five-step process for estimation problems (EMC³) to construct a 95% confidence interval for the proportion of adults in the United States who believe that global climate change is a major threat to the well-being of the United States. (Hint: See Example 9.4. Enter your answer using interval notation. Round your numerical values to three decimal places.) 0.556, 0.610 X Interpret the interval. O There is a 95% chance that the mean number of all adults in the United States who believe that global climate change is a major threat to the well-being of the United States is directly in the middle of this confidence interval. O We are 95% confident that the mean number of all adults in the United States who believe that…arrow_forward
- The 95% Confidence Interval for the weights (in pounds) of a special type of rock has found to be 4.19, 7.48. What will be the margin of error? (Hint: Sample mean +/- margin of error = confidence interval)arrow_forwardAn investigator conducts a study to investigate whether there is a difference in mean peak expiratory flow (PEF) in children with chronic bronchitis as compared to those without. Data on PEF are collected and summarized below. Construct a 95% confidence interval for the mean PEF in children without chronic bronchitis. b. How many children would be required to ensure that the margin of error in (a) does not exceed 10 units? What is the margin of error? Group # Children Mean PEF Std Dev PEF Chronic Bronchitis 25 281 68 No Chronic Bronchitis 25 319 74 a. 95% CI ( , )arrow_forwardIn a study of speed dating, male subjects were asked to rate the attractiveness of their female dates, and a sample of the results is listed below (1-not attractive; 10 = extremely attractive). Construct a confidence interval using a 90% confidence level. What do the results tell about the mean attractiveness ratings of the population of all adult females? 6,9,3,10,4,5,6,8,8,8,5,9 What is the confidence interval for the population mean μ? (Round to one decimal place as needed ) < μ <arrow_forward
- A 90% confidence interval for the mean of airline reservations being canceled on the day of the flight is between 2.68 and 9.42 reservations. What is the point estimate of the mean of reservations that are canceled on the day of the flight?arrow_forwardWhat prerequisites should students have the knowledge of before calculating the confidence intervals for two population means?arrow_forwardIt is known that the overall job satisfaction (score range 0-10) of professors follows a normal distribution. The job satisfaction of 16 SUNY professor shows blow using a histogram. Calculate the 95% CI to estimate the professor population's average job satisfaction level and interpret the 95% CI. List two ways that you could use to get a narrower confidence level. Which way is better? Why?arrow_forward
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