Find the critical values x²1-a/2 and x²a/2 for a 80% confidence level and a sample size of n = 10. X²1-x/2 = (Round to three decimal places as needed.) X²α/2 = (Round to three decimal places as needed.)

Find the critical value x²R corresponding to a sample size of 19 and a confidence level of 99 percent. X²R = (Round to 3 decimals)

A sample size of 100 from a population having a standard deviation =8 produced a mean of 40. The 99% confidence interval for the population mean (rounded to two decimals) is:

Given two independent random samples with the following results: n1=12x‾1=73s1=27n1=12x‾1=73s1=27   n2=12x‾2=102s2=22n2=12x‾2=102s2=22 Use this data to find the 95%95% confidence interval for the true difference between the population means. Assume that the population variances are equal and that the two populations are normally distributed.   Step 1 of 3 :   Find the point estimate that should be used in constructing the confidence interval.

Create a 85% confidence interval for a population mean from a sample of size 65 with sample mean a = 11.7. The population standard deviation is known to be o = %3D 3.28. [three decimal accuracy] [three decimal accuracy]

7. What is the 95% confidence interval for the difference in the population means, µ1 - µ2, given the data from the two independent samples: n1 =56, x1= 58.2, s1= 4.3, n2=45, x2=60.2, s2=5.5 B. [-3.28 , -0.72] C. [-3.60, -0.40] D. [-3.65 , -0.35] A. [-3.96 , -0.04] 8. What is the 98% confidence interval for the difference in the population means, µ1 - µ2, given: n1= 22, x1= 41.4, s1= 5.9, n2= 19, x2= 43.2, s2= 6.5  D. [-3.48 , -0.12] B. [-3.07 , -0.53] A. [-3.12, -0.48] C. [-3.18, -0.42]

n=10 b = 0.50 sb = 0.02 α=0.05 find the confidence interval for β.

You are going to create a 99% confidence interval for the mean amount ofsugar in coffee shop specialty drinks. You know the population standarddeviation is σ = 5.9 grams. You want your confidence interval to have amargin of error of 0.25 grams. How big should your sample size be to obtainthis margin of error?

Calculate the point estimate.

Bob selects independent random samples from wo populations and obtains the values pi 0.700 and p2 confidence interval for p1 – P2 and gets: 0.500. He constructs the 95% 0.200 ± 1.96(0.048) = 0.200 ±0.094. %3| Note that 0.048 is called the estimated standard error of pi – P2 (the ESE of the estimate). Tom wants to estimate the mean of the success rates: Pi + p2 (a) Calculate Tom's point estimate. (b) Given that the estimated standard er- ror of (p1 + p2)/2 is 0.024, calculate the 95% confidence interval estimate of (Pi + P2)/2. Hint: The answer has our usual form: Pt. est. ±1.96 × ESE of the estimate.