Find the conditional probability of the given event when two fair dice (one red and one green) are rolled. The red one is 1, given that the green one is 1. Step 1 Begin by considering the sample spaces and the probabilities of the outcomes. Recall that for the experiment of rolling two dice (the first one red and the second one green) and observing the face-up number on each die, the sample space S is the following 36-element set. |(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 9, (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (б, 2), (6, 3), (6, 4), (6, 5), (6, 6) S = Recall also that since both dice are fair, the outcomes are equally likely; that is, the probability of any one outcome is the same as that of any other. Because probabilities are never negative and the sum of the probabilities of all outcomes in a sample space must be 1, the probability of any one of the 36 equally likely outcomes is

College Algebra
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ISBN:9781337282291
Author:Ron Larson
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Chapter8: Sequences, Series,and Probability
Section8.7: Probability
Problem 4ECP: Show that the probability of drawing a club at random from a standard deck of 52 playing cards is...
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Find the conditional probability of the given event when two fair dice (one red and one green) are rolled.
The red one is 1, given that the green one is 1.
Step 1
Begin by considering the sample spaces and the probabilities of the outcomes.
Recall that for the experiment of rolling two dice (the first one red and the second one green) and observing
the face-up number on each die, the sample space S is the following 36-element set.
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),
(2, 1), (2, 2), (2, 3), (2, 9, (2, 5), (2, 6),
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6),
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
S =
Recall also that since both dice are fair, the outcomes are equally likely; that is, the probability of any one
outcome is the same as that of any other.
Because probabilities are never negative and the sum of the probabilities of all outcomes in a sample space
must be 1, the probability of any one of the 36 equally likely outcomes is
Transcribed Image Text:Find the conditional probability of the given event when two fair dice (one red and one green) are rolled. The red one is 1, given that the green one is 1. Step 1 Begin by considering the sample spaces and the probabilities of the outcomes. Recall that for the experiment of rolling two dice (the first one red and the second one green) and observing the face-up number on each die, the sample space S is the following 36-element set. (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 9, (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6) S = Recall also that since both dice are fair, the outcomes are equally likely; that is, the probability of any one outcome is the same as that of any other. Because probabilities are never negative and the sum of the probabilities of all outcomes in a sample space must be 1, the probability of any one of the 36 equally likely outcomes is
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