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Find the average velocity during each time period. s = s(t) = 3 sin(tt)+ 2 cos(Tt). (i) On the interval [1, 2], Vavg s(2)–s(1) 2-(-2) — 4.00 ст/s. 2-1 1 (ii) On the interval [1, 1.1], vavg s(1.1)-s(1) -2.829-(-2) —8.29 ст/s. 1.1–1 0.1

Find the average velocity during each time period. s = s(t) = 3 sin(tt)+ 2 cos(Tt). (i) On the interval [1, 2], Vavg s(2)–s(1) 2-(-2) — 4.00 ст/s. 2-1 1 (ii) On the interval [1, 1.1], vavg s(1.1)-s(1) -2.829-(-2) —8.29 ст/s. 1.1–1 0.1

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.1: Solutions Of Elementary And Separable Differential Equations
Problem 18E: Find the general solution for each differential equation. Verify that each solution satisfies the...
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Okay so the problem is already solved , but how on earth are they getting the values in the second step? (how did the asnwer get -2.829)

Find the average velocity during each time period. s = s(t) = 3 sin(nt)+ 2 cos(Tt). (i) On the interval [1, 2], Vavg s(2)-s(1) 2-(-2) — 4.00 ст/s. 2–1 1 (ii) On the interval [1, 1.1], Vavg s(1.1)-s(1) -2.829-(-2) 0.1 -8.29 cm/s. 1.1–1
Transcribed Image Text:Find the average velocity during each time period. s = s(t) = 3 sin(nt)+ 2 cos(Tt). (i) On the interval [1, 2], Vavg s(2)-s(1) 2-(-2) — 4.00 ст/s. 2–1 1 (ii) On the interval [1, 1.1], Vavg s(1.1)-s(1) -2.829-(-2) 0.1 -8.29 cm/s. 1.1–1
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