Find the area under the standard normal distribution curve to the left of =z−3.14 and to the right of =z0.78. Use a graphing calculator and round the answer to four decimal places. The area is

Determine the area under the standard normal curve that lies between z=-1.50 and z=1.50. [Please write you answer as a whole  percentage]

Find the area under the standard normal distribution curve to the right of z=1.59 . Use The Standard Normal Distribution Table and enter the answer to 4 decimal places.   The area to the right of the z value is:

Find the area under the standard normal curve to the left of z = -0.95. Round your answer to four decimal places, if necessary.

Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1. 2= -0.81 z=1.21 The area of the shaded region is (Round to four decimal places as needed.)

Find the area betweenx = 9.5 and x = 27 under a normal distribution curve with = 20 and o = 4. Round your answer to four decimal places. A = i

Determine the area under the standard normal curve that lies between (a) Z= - 1.49 and Z= 1.49, (b) Z = - 2.42 and Z = 0, and (c) Z= - 0.37 and Z = 1.74. Click the icon to view a table of areas under the normal curve. Tables of Areas under the Normal Curve .... (a) The area that lies between Z= - 1.49 and Z= 1.49 is (Round to four decimal places as needed.) (b) The area that lies between Z = - 2.42 and Z = 0 is TABLE V (Round to four decimal places as needed.) Standard Normal Distribution .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 (c) The area that lies between Z= - 0.37 and Z= 1.74 is Area 0.0003 0.0003 0.0003 0.0003 0.0002 -3.4 -3.3 0.0003 0.0003 0.0003 0.0003 0.0003 (Round to four decimal places as needed.) 0.0005 0.0007 0.0005 0.0006 0,0009 0,0013 0.0005 0.0004 0.0004 0.0004 0.0004 0.0004 0.0004 0.0003 0.0006 0.0008 0.0005 0.0007 0,0010 -3.2 0.0007 0.000 0.0006 0.0006 0.000 0.0005 -3.1 0.0010 0.0009 0.0009 0.0008 0.0008 0.0008 0.0007 -3.0 0.0013 0.0013 0.0012 0.0012 0.0011 0.0011…