Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1. 2-082 2 121

Calculate the z-score representing the bottom 10% of an approximately normal distribution. (Use a table or technology. Round your answer to two decimal places.)

Use the normal distribution of IQ scores , which has a mean of 90 and a standard deviation of 14, and the following table with the standard scores and percentiles for a normal distribution to find the indicated quantity. view the table: Standard Scores and Percentiles for a Normal Distribution (cumulative values from the left) Full data set     Open in StatCrunch   +   Copy to Clipboard   +   Open in Excel   + Standard score ​% Standard score ​% minus−3.0 0.13 0.1 53.98 minus−2.5 0.62 0.5 69.15 minus−2 2.28 0.9 81.59 minus−1.5 6.68 1 84.13 minus−1 15.87 1.5 93.32 minus−0.9 18.41 2 97.72 minus−0.5 30.85 2.5 99.38 minus−0.1 46.02 3 99.87 0 50.00 3.5 99.98 The percentage of scores between 62 and 118 is ________%.  Round to two decimal places as needed.

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Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1. The area of the shaded region is

Find Pas, that is find 90 percentile of z-score from the standard normal distribution. 6.

A simple random sample of 736 photographers found that 65% plan to purchase new equipment within the next year. Data follows the normal curve. What is the SD of the sample? Round to three decimal places. Typed and correct answer please. I ll rate accordingly.