Find the area of the indicated region under the standard normal curve. Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. ... -1 0 1.6 + O G

You are conducting a test of independence for the claim that two different populations have the same proportions of the following two characteristics. Here is the sample data. Population Population #1 Category #2 A 43 33 В 32 18 The expected frequencies for this table would be Population Population #1 Category #2 A В What is the chi-square test-statistic for this data? Report all answers accurate to three decimal places.

Area under the standard normal distribution to the left of Z (page 2) D Z 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 1.1 1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9 2.0 .09 .00 .01 .02 .03 .04 .05 .06 .07 .08 5000 .5040 .5080 5120 5160 .5199 5239 5279 5319 .5359 5398 .5438 .5478 .5517 5557 .5596 .5636 5675 5714 .5753 5793 .5832 .5871 5910 5948 5987 .6026 .6064 .6103 .6141 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517 .6554 .6591 .6628 .6664 .6700 .6736 .6772 .6808 .6844 .6879 .6915 .6950 .6985 .7019 .7054 .7088 .7123 .7157 .7190 .7224 .7257 .7291 .7324 .7357 .7389 .7422 .7454 .7486 .7517 .7549 .7580 .7611 .7642 .7673 .7704 .7734 .7764 7794 .7823 .7852 .7881 .7910 .7939 .7967 .7995 .8023 .8051 .8078 .8106 .8133 .8159 .8186 .8212 8238 .8264 .8289 .8315 .8340 .8365 .8389 8413 .8438 .8461 .8485 .8508 .8531 .8554 .8577 .8599 .8621 .8643 .8665 .8686 .8708 .8729 .8749 .8770 8790 8810 .8830 .8849 .8869 .8888 .8907 .8925 .8944 .8962 .8980 .8997 .9032 .9049 .9066 .9082 .9099 9115 .9131 .9147…

Find the indicated area under the standard normal curve. To the right of z = 1.41 Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. The area to the right of z= 1.41 under the standard normal curve is (Round to four decimal places as needed.)