Find tan a. V[ ? (V5, -/7)

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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**Title: Finding the Tangent of an Angle α**

**Objective:**
Learn how to find the tangent of an angle given a point on the coordinate plane.

**Concept Overview:**

In this diagram, we are tasked with finding the tangent of the angle α, which is formed by a vector \( r \) originating from the origin and terminating at the point \((\sqrt{5}, -\sqrt{7})\).

**Diagram Explanation:**

- A coordinate plane is depicted with both horizontal and vertical axes.
- The vector \( r \) makes an angle α with the horizontal axis.
- The coordinates of the endpoint of the vector are \((\sqrt{5}, -\sqrt{7})\).

**Steps to Find \(\tan \alpha\):**

The tangent of an angle in a right triangle is the ratio of the opposite side to the adjacent side:

\[
\tan \alpha = \frac{\text{Opposite}}{\text{Adjacent}}
\]

For a point \((x, y)\),

- \(\tan \alpha = \frac{y}{x}\)

Plugging in the coordinates:

- \(\tan \alpha = \frac{-\sqrt{7}}{\sqrt{5}}\)

**Conclusion:**

The tangent of angle α is \(\frac{-\sqrt{7}}{\sqrt{5}}\), which simplifies the trigonometric analysis of the vector in relation to the coordinate plane. Understanding this ratio is fundamental in relating algebraic expressions to geometric representations in trigonometry.
Transcribed Image Text:**Title: Finding the Tangent of an Angle α** **Objective:** Learn how to find the tangent of an angle given a point on the coordinate plane. **Concept Overview:** In this diagram, we are tasked with finding the tangent of the angle α, which is formed by a vector \( r \) originating from the origin and terminating at the point \((\sqrt{5}, -\sqrt{7})\). **Diagram Explanation:** - A coordinate plane is depicted with both horizontal and vertical axes. - The vector \( r \) makes an angle α with the horizontal axis. - The coordinates of the endpoint of the vector are \((\sqrt{5}, -\sqrt{7})\). **Steps to Find \(\tan \alpha\):** The tangent of an angle in a right triangle is the ratio of the opposite side to the adjacent side: \[ \tan \alpha = \frac{\text{Opposite}}{\text{Adjacent}} \] For a point \((x, y)\), - \(\tan \alpha = \frac{y}{x}\) Plugging in the coordinates: - \(\tan \alpha = \frac{-\sqrt{7}}{\sqrt{5}}\) **Conclusion:** The tangent of angle α is \(\frac{-\sqrt{7}}{\sqrt{5}}\), which simplifies the trigonometric analysis of the vector in relation to the coordinate plane. Understanding this ratio is fundamental in relating algebraic expressions to geometric representations in trigonometry.
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