Find sin(x/2) =  cos(x/2) =  tan(x/2) =  Given tan(x) = 2sqrt2    0 degrees < x< 90 degrees

Find f. f '(x) = cos(x), f(0) = 1, f'(0) = 8, f "(0) = 6 f(x) = sin x + 7x²/2 + 7x + 8 Need Help? Read It

Let h(x) = tan(2x + 5). h'(x) h"(x) = = 2 sec (2x+5)(2) OF ४

Use that tan (x) · sec* (x) = tan? (x) · sec³ (x) · (sec(x) tan(x)) and the Pythagorean identity for tan? (x). Use that tan (x) · sec*(x) = tan³ (x) • sec² (x) · (sec2 (x)) and the Pythagorean identity for sec? (x).

Show that sin? (x) cos(x) = sec(x) – cos(x)

Find sec(?) if tan(?) = 21/20 and cos(?)>0.sec(?) =

Find f"(x), where f(x) = tan-(sin x2019)

(sec(x) + 1)/(tan x) = (sin x)/(1 - cos x)

Verify that 2tan (x/2)= (sin2x+1-cos2)/(sin x(1+cos x)