"find scalars c1, c2, and c3 for which the equation is satisfied.
19. c1(1, −1, 0) + c2(3, 2, 1) + c3(0, 1, 4) = (−1, 1, 19)
Given,
c1(1, −1, 0) + c2(3, 2, 1) + c3(0, 1, 4) = (−1, 1, 19)
That is
C1(i-j) + C2(3i+2j+k) + C3(j+4k) = (-i+j+19)
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