Find P(Z < -1.26) where Z is the standard normal random variable. Round to 4 decimal places. Answer:

Find P(-1.77 < Z ≤ 2.32) where Z is the standard normal random variable. Answer: Round to 4 decimal places.

Find the standard deviation for the binomial random variable. Round to 4 decimal n= 90 Π= .60

Given that z is a standard normal random variable, find z for each situation (to 2 decimals). The area to the left of z is 0.6591. The area to the right of z is 0.3409.

nd markers without ink. Assume that the box contains 17 markers: 12 that contain ink and 5 tha ontain ink. A sample of 8 markers is selected and a random variable Y is defined as the number arkers selected which do not have ink. ow many different values are possible for the random variable Y? Part 2

The accompanying table describes results from groups of 10 births from 10 different sets of parents. The random variable x represents the number of girls among 10 children. Use the range rule of thumb to determine whether 1 girl in 10 births is a significantly low number of girls. Click the icon to view the table. Use the range rule of thumb to identify a range of values that are not significant. The maximum value in this range is girls. (Round to one decimal place as needed.) - X Probability Distribution for x Number of Girls x 0 1 2 3 4 5 6 7 8 9 10 Print Get P(x) 0.002 0.013 0.044 0.115 0.208 0.234 0.201 0.115 0.043 0.019 0.006 Done k answer

Please help with unanswered parts (d,e,f,g)

answer in30mins pls

Find the indicated probability for the standard normal Z: P(-2.77 < Z < 2.95) Select one: a. 0.0044 b. 0.4956 C. 0.9956 d. 0.9984

Use the Standard Normal Distribution Table to find the area (probability) of the indicated shaded region. Z1 = – 0.40 and Z2 = 1.52 %3D Z1 Z2 O 0.9726 O 0.5911 O 0.3446 O 0.9357 O 0.4089