Find out the ΔH (in kJ) for the reaction: 2C(s) + H₂(g) → C₂H₂(g) Given- C(s) + O₂(g) → CO₂(g)   (ΔΗ = -393.5 kJ) H₂(g) + 1/2O₂(g) → H₂O(l)   (ΔΗ = -285.8 kJ) 2 C2H2(g) + 5 O2(g) → 4 CO2(g) + 2 H2O(I)   (ΔH = -2598.8 kJ)

Calculate ΔHrxnΔHrxn for the following reaction:   CH4(g)+4Cl2(g)→CCl4(g)+4HCl(g) given these reactions and their ΔHΔH values: C(s)+ 2H2(g) →CH4(g), ΔH=−74.6 kJ C(s)+2Cl2(g) →CCl4(g),ΔH=−95.7 kJ H2(g)+Cl2(g) →2HCl(g), ΔH=−184.6 kJ

1)What is the specific heat if 24.8 g of a metal absorbs 275 J of energy and the temperature rises from 20.2 °C to 24.5 °C? 2)Calculate the enthalpy for the combustion of 1.0 mol CH4, at 25 °C and 1 atm. ΔΗ (kJ/mol) CHĄ(g) + 02(g) –→ CO2(g) + H20(1) CHĄ(g) -74.6 CO2(g) -393.5 H,0(1) -285.8

The combustion of ethane, C2H6, has an enthalpy change of -2857.4 KJ for the reaction as written below. Calculate ΔH° for the conbustion of 15.0 g of C2H6.  2 C2H6(g) +7 O2(g) → 4 CO2(g) + 6 H2O(g) ΔrH° = -2857.3 KJ/mol-rxn

Find the ΔH (kJ) for the reaction below, given the following reactions and subsequent ΔH values: N2(g) + 2O2(g) → 2NO 2(g) N2(g) + 3H2(g) → 2NH3(g) ΔH = -115 kJ 2NH3(g) + 4H2O(l) → 2NO2(g) + 7H2(g) ΔH = -142.5 kJ H2O(l) → H2(g) + 1/2O 2(g) ΔH = -43.7 kJ (Supply answer up to the 1st decimal point)

Calculate ΔHrxn for 2NOCl(g) → N2(g) + O2(g) + Cl2(g) given the following set of reactions: 1/2 N2(g) + 1/2 O2(g) → NO(g) ΔHrxn = 90.3 kJ NO(g) + 1/2 Cl2(g) → NOCl(g) ΔHrxn = −38.6 kJ

Use the data given below to find the enthalpy of reaction for the following reaction: CaCO3(s) → CaO(s) + CO2 (g) AH (kJ/mol) СаСОз (s) -1207 CaO(s) -635.5 CO2 (g) -393.5 -2236 kJ -178 kJ +178 kJ O -1449 kJ -2058 kJ

Using the ΔHf values in the appendix, calculate the ΔH of each reaction below.                          4 NH3(g) +  O2(g)  →  2 N2H4(g)  +  2 H2O(l)

Determine the ΔH of the following reactions. 1.) CH4 (g) + 2 O2 (g) à CO2 (g) + 2 H2O (l)     2.) CH4 (g) + 2 O2 (g) à CO2 (g) + 2 H2O (g)

Use the following data to calculate ΔHf for hexane, C6H14(ℓ). Include negative sign if appropriate.               C6H14(ℓ) +19/2 O2(g) → 6CO2(g) + 7H2O(ℓ)    ΔHrxn = -4198.4 kJ                   ΔHf  of CO2(g) = -393.5 kJ/mol          ΔHf  of H2O(ℓ) = -285.8 kJ/mol