Find k such that the line is tangent to the graph of the function. Line Function f(x) = k√x y = 3x + 12 Step 1 We want a value of k that will make the line y tangent to the function f(x). In order for y to be tangent to f(x), then y will touch f(x) at a point. At that point, the two equations are equal. f(x) = y k√x = 3 x + 12 [[ 12 Step 2 If y is tangent to f(x) at the point x, the slope of y must equal the derivative of f(x). To determine this we simply take the derivative of each side of the equation. k√x = 3x + 12 ]]= (3x+12]
Find k such that the line is tangent to the graph of the function. Line Function f(x) = k√x y = 3x + 12 Step 1 We want a value of k that will make the line y tangent to the function f(x). In order for y to be tangent to f(x), then y will touch f(x) at a point. At that point, the two equations are equal. f(x) = y k√x = 3 x + 12 [[ 12 Step 2 If y is tangent to f(x) at the point x, the slope of y must equal the derivative of f(x). To determine this we simply take the derivative of each side of the equation. k√x = 3x + 12 ]]= (3x+12]
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter9: Quadratic Functions And Equations
Section9.6: Solving Quadratic Equations By Using The Quadratic Formula
Problem 64PFA
Related questions
Question
![Find k such that the line is tangent to the graph of the function.
Function
Line
f(x) = k√√x
y = 3x + 12
Step 1
We want a value of k that will make the line y tangent to the function f(x). In order for y to be tangent to f(x), then y will touch f(x) at a point. At that point, the two
equations are equal.
f(x) = y
k√x = 3 3 x + 12
Submit
Step 2
If y is tangent to f(x) at the point x, the slope of y must equal the derivative of f(x). To determine this we simply take the derivative of each side of the equation.
k√√x=
d
dx
12
= 3x + 12
=
Skin (you cannot come back)
-[3x + 12]
dx
[3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff9b6a03f-2298-4441-ab19-fb50f28ec42f%2F2b2d493c-88d5-46ff-8c57-caf8d87762e9%2Fxbae98_processed.png&w=3840&q=75)
Transcribed Image Text:Find k such that the line is tangent to the graph of the function.
Function
Line
f(x) = k√√x
y = 3x + 12
Step 1
We want a value of k that will make the line y tangent to the function f(x). In order for y to be tangent to f(x), then y will touch f(x) at a point. At that point, the two
equations are equal.
f(x) = y
k√x = 3 3 x + 12
Submit
Step 2
If y is tangent to f(x) at the point x, the slope of y must equal the derivative of f(x). To determine this we simply take the derivative of each side of the equation.
k√√x=
d
dx
12
= 3x + 12
=
Skin (you cannot come back)
-[3x + 12]
dx
[3
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