Find five random employees from a random department The image displays a table with three columns titled DEPTNO, DNAME, and LOC. Below is a transcription of the data presented in the table:1. **DEPTNO: 10** - **DNAME: ACCOUNTING** - **LOC: NEW YORK**2. **DEPTNO: 20** - **DNAME: RESEARCH** - **LOC: DALLAS**3. **DEPTNO: 30** - **DNAME: SALES** - **LOC: CHICAGO**4. **DEPTNO: 40** - **DNAME: OPERATIONS** - **LOC: BOSTON**This table lists various departments identified by their department numbers, names, and locations. The image shows a table with the following columns and data:- **EMPNO (Employee Number):** - 7839 - 7566- **ENAME (Employee Name):** - KING - JONES- **JOB (Job Title):** - PRESIDENT - MANAGER- **MGR (Manager Number):** - (null) for KING - 7839 for JONES- **HIREDATE (Hire Date):** - 17-NOV-81 for KING - 02-APR-81 for JONES- **SAL (Salary):** - 5000 for KING - 2975 for JONES- **COMM (Commission):** - (null) for both KING and JONES- **DEPTNO (Department Number):** - 10 for KING - 20 for JONES**Explanation:**This table represents employee data, where each row corresponds to an individual employee's details. The columns include identifiers like employee number and name, job information, manager references, hire date, and financial details such as salary and commission. Null values indicate missing data in the manager and commission columns for some entries.

Syntax to select a random record: SELECT column FROM (SELECT column FROM table…

Answered: Find five random employees from a…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

Find five random employees from a random department

The image displays a table with three columns titled DEPTNO, DNAME, and LOC. Below is a transcription of the data presented in the table:

1. **DEPTNO: 10**
- **DNAME: ACCOUNTING**
- **LOC: NEW YORK**

2. **DEPTNO: 20**
- **DNAME: RESEARCH**
- **LOC: DALLAS**

3. **DEPTNO: 30**
- **DNAME: SALES**
- **LOC: CHICAGO**

4. **DEPTNO: 40**
- **DNAME: OPERATIONS**
- **LOC: BOSTON**

This table lists various departments identified by their department numbers, names, and locations.

The image shows a table with the following columns and data:

- **EMPNO (Employee Number):**
- 7839
- 7566

- **ENAME (Employee Name):**
- KING
- JONES

- **JOB (Job Title):**
- PRESIDENT
- MANAGER

- **MGR (Manager Number):**
- (null) for KING
- 7839 for JONES

- **HIREDATE (Hire Date):**
- 17-NOV-81 for KING
- 02-APR-81 for JONES

- **SAL (Salary):**
- 5000 for KING
- 2975 for JONES

- **COMM (Commission):**
- (null) for both KING and JONES

- **DEPTNO (Department Number):**
- 10 for KING
- 20 for JONES

**Explanation:**

This table represents employee data, where each row corresponds to an individual employee's details. The columns include identifiers like employee number and name, job information, manager references, hire date, and financial details such as salary and commission. Null values indicate missing data in the manager and commission columns for some entries.

Expert Solution

Step 1

Syntax to select a random record:

SELECT column FROM (SELECT column FROM table ORDER BY dbms_random.value) WHERE rownum =1

By using the above syntax, Initially, a random department (DEPTNO) is retrieved from the DEPT table. Using DEPTNO, 5 random employee records are retrieved from the EMP table.

NOTE: Sample Data is considered to implement query on EMP and DEPT table.

Step 2

Data in EMP Table:

Data in DEPT table:

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