Find e such that the function -5 I ≤C f(x) = {10z z>c is continuous everywhere. c= 10-30

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter6: Applications Of The Derivative
Section6.CR: Chapter 6 Review
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The image contains a piecewise function \( f(x) \) and a problem statement asking to find the value of \( c \) such that the function is continuous everywhere. The function is defined differently for values of \( x \) less than or equal to \( c \) and for values of \( x \) greater than \( c \).

Below is the complete transcription:

---

**Find \( c \) such that the function**

\[ f(x) = \begin{cases} 
x^2 - 5 & \text{if } x \leq c \\
10x - 30 & \text{if } x > c 
\end{cases} \]

**is continuous everywhere.**

\[ c = \ \underline{\hspace{2cm}} \]

---

This piecewise function has two different expressions: \( x^2 - 5 \) for \( x \leq c \) and \( 10x - 30 \) for \( x > c \). To find the value of \( c \) that makes \( f(x) \) continuous everywhere, the two expressions must meet at \( x = c \). This means that the limit from the left-hand side of \( c \) and the limit from the right-hand side of \( c \) must be equal, ensuring that there is no discontinuity at \( x = c \).

There were no graphs or diagrams included in the image that need further explanation.
Transcribed Image Text:The image contains a piecewise function \( f(x) \) and a problem statement asking to find the value of \( c \) such that the function is continuous everywhere. The function is defined differently for values of \( x \) less than or equal to \( c \) and for values of \( x \) greater than \( c \). Below is the complete transcription: --- **Find \( c \) such that the function** \[ f(x) = \begin{cases} x^2 - 5 & \text{if } x \leq c \\ 10x - 30 & \text{if } x > c \end{cases} \] **is continuous everywhere.** \[ c = \ \underline{\hspace{2cm}} \] --- This piecewise function has two different expressions: \( x^2 - 5 \) for \( x \leq c \) and \( 10x - 30 \) for \( x > c \). To find the value of \( c \) that makes \( f(x) \) continuous everywhere, the two expressions must meet at \( x = c \). This means that the limit from the left-hand side of \( c \) and the limit from the right-hand side of \( c \) must be equal, ensuring that there is no discontinuity at \( x = c \). There were no graphs or diagrams included in the image that need further explanation.
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