Find dy/dx by implicit differentiation. Then find the slope of the graph at the given point. (If an answer is undefined, enter UNDEFINED.) 4exy - x = 0, (4,0) dy = At (4,0): dy

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Question
### Implicit Differentiation and Slope Calculation

**Problem Statement:**

Find \(\frac{dy}{dx}\) by implicit differentiation. Then find the slope of the graph at the given point. (If an answer is undefined, enter UNDEFINED.)

Equation: \(4e^{xy} - x = 0\) 
Given Point: \((4, 0)\)

**Steps:**

1. **Implicit Differentiation:**

   Differentiate \(4e^{xy} - x = 0\) implicitly with respect to \(x\):

   \[
   \frac{d}{dx}(4e^{xy}) - \frac{d}{dx}(x) = 0
   \]

   Using the chain rule for \(4e^{xy}\):

   \[
   4e^{xy} \left( x \frac{dy}{dx} + y \right)  - 1 = 0
   \]

2. **Solving for \(\frac{dy}{dx}\):**

   Rearrange the equation to solve for \(\frac{dy}{dx}\):

   \[
   4e^{xy} \left( x \frac{dy}{dx} + y \right) - 1 = 0
   \]

   \[
   4e^{xy} x \frac{dy}{dx} + 4e^{xy} y - 1 = 0
   \]

   \[
   4e^{xy} x \frac{dy}{dx} = 1 - 4e^{xy} y
   \]

   \[
   \frac{dy}{dx} = \frac{1 - 4e^{xy} y}{4e^{xy} x}
   \]

3. **At Point \((4, 0)\):**

   Substitute \(x = 4\) and \(y = 0\) into the differentiated expression:

   \[
   \frac{dy}{dx} = \frac{1 - 4e^{4 \cdot 0} \cdot 0}{4e^{4 \cdot 0} \cdot 4}
   \]

   Simplify the expression:

   \[
   \frac{dy}{dx} = \frac{1 - 0}{4 \cdot 4} = \frac{1
Transcribed Image Text:### Implicit Differentiation and Slope Calculation **Problem Statement:** Find \(\frac{dy}{dx}\) by implicit differentiation. Then find the slope of the graph at the given point. (If an answer is undefined, enter UNDEFINED.) Equation: \(4e^{xy} - x = 0\) Given Point: \((4, 0)\) **Steps:** 1. **Implicit Differentiation:** Differentiate \(4e^{xy} - x = 0\) implicitly with respect to \(x\): \[ \frac{d}{dx}(4e^{xy}) - \frac{d}{dx}(x) = 0 \] Using the chain rule for \(4e^{xy}\): \[ 4e^{xy} \left( x \frac{dy}{dx} + y \right) - 1 = 0 \] 2. **Solving for \(\frac{dy}{dx}\):** Rearrange the equation to solve for \(\frac{dy}{dx}\): \[ 4e^{xy} \left( x \frac{dy}{dx} + y \right) - 1 = 0 \] \[ 4e^{xy} x \frac{dy}{dx} + 4e^{xy} y - 1 = 0 \] \[ 4e^{xy} x \frac{dy}{dx} = 1 - 4e^{xy} y \] \[ \frac{dy}{dx} = \frac{1 - 4e^{xy} y}{4e^{xy} x} \] 3. **At Point \((4, 0)\):** Substitute \(x = 4\) and \(y = 0\) into the differentiated expression: \[ \frac{dy}{dx} = \frac{1 - 4e^{4 \cdot 0} \cdot 0}{4e^{4 \cdot 0} \cdot 4} \] Simplify the expression: \[ \frac{dy}{dx} = \frac{1 - 0}{4 \cdot 4} = \frac{1
**Find \( \frac{dy}{dx} \) by implicit differentiation. Then find the slope of the graph at the given point. (If an answer is undefined, enter UNDEFINED.)**

Given equation: \( 4e^{xy} - x = 0 \), at point \( (4, 0) \).

\[ \frac{dy}{dx} = \ \]

\[ \text{At} \ (4, 0): \ \frac{dy}{dx} = \ \]
Transcribed Image Text:**Find \( \frac{dy}{dx} \) by implicit differentiation. Then find the slope of the graph at the given point. (If an answer is undefined, enter UNDEFINED.)** Given equation: \( 4e^{xy} - x = 0 \), at point \( (4, 0) \). \[ \frac{dy}{dx} = \ \] \[ \text{At} \ (4, 0): \ \frac{dy}{dx} = \ \]
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