Find dy dx and d²y dx² x = et, y = te-t

Q: find dy/dx, y=tanx-secx

A:

Q: H.w: find dy dx 1- y=-10x+3cosx

A:

Q: dy 2y 1. dx 2y3 %3D

A:

Q: Find dy/dx x = 2eθ , y = e−θ/2

A: Given:  x = 2eθ  and y = e−θ/2

Q: Differentiate implicitly to find dy = dx 2 X +y2 dy dx - y2 = 2 X

A:

Q: dy dx Find when x = Vt and yt² +2+³ =

A: To find the derivative with given parametric equations

Q: dy Find for y = dx /9 – x4 dy dx

A:

Q: Find dy/dx in terms of x and y if x = 10√/y. X

A:

Q: 2. Let y = x? 4x2 . LA. Find "dy". B. Find the value of "dy" when x = 4 and dæ = 0.01.

A:

Q: dy Find if y = n4. dx dy dx

A:

Q: Evaluate

A:

Q: Find dy/dx. x2 - 4y2 = 3x3y4

A: From the given data:

Q: Find for y = dx dy dx 1 C

A: On solving this we will get

Q: Find dy/dx. dy dx x=√t y = 4-t

A: To find the derivative of given function.

Q: find dy/dx ,y= cosx

A:

Q: dy Find dx for y = (1+ æ)* || Ans=

A: Here we can find the derivative as below.

Q: dy Find for y = dx dy dx 1 13

A: The required derivative is given below

Q: Find dy/dx by differentiating implicitly if x + xy − 2x³ = 1.

A:

Q: dy 1 dx sec?y

A:

Q: Find dy dx dy dx 11 x = √t, y = 4 - t

A:

Q: 4 y = (-2а —4) 3 1 Find dy/dx

A: We will further simplify the function and then differentiate it using the chain rule of…