Find current thru – j5 ohm capacitive reactance use any method.
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- An rms voltage of 22.2 V with a frequencyof 1.00 kHz is applied to a 0.290-mH inductor. (a) What is the rmscurrent in this circuit? (b) By what factor does the current changeif the frequency of the voltage is doubled? (c) Calculate the current for a frequency of 2.00 kHz60. Design a circuit to limit a 20 V rms sinusoidal voltage to a maximum positive amplitude of 10 V and a maximum negative amplitude of -5 V using a single 14 V de voltage source. 61 Datermine the volto in the girRuit F Figura 1 1?Te netuork show in ope eating in the tondy Thandy state wilh sinussidal vol voltage douce and V, 2 Sin2t delernine the volla fe Va(t) 2178 F Va 2178F 2173F IH
- Please show your detailed solution Number 14 The current in a series inductive circuit is 7.5 A at 25 Hz. The circuit takes 425 W, and the power factor is 0.47. The resistance of the circuit is A. 7.32 ohms C. 7.98 ohms B. 7.86 ohms D. 7.56 ohms1) Two identical voltage waveforms of difference phase angles are shown in Figure B. Write down the expression of waveforms A and B clearly. HUS Voltage (V) 8 0 K/N B 7: ST ot5 The voltmeters in the figure measure RMS voltages. If V, = 23 V and V, = 14.5V what is V3? %3D C R eee V2 V3 23 V None of them 8.5 V 4.5V 37.5 V O 14.5 V
- A solenoid with an inductance of 0.25 H and a resistance of 100 Q is connected to a 120-V 60-Hz source. The current is: Please check the closest answer that applies. X L 120 V 60 Hz O0.226 2-16.3° A O0.224 2-31.2° A LO7. In a pure inductive circuit, the phase angle between the voltage waveform and current waveform will havephase shift * 180 deg O deg 45 deg O 90 deg 8. Why do we say the "voltage across" or "the voltage with respect to?" Why can't we just say voltage? * Voltage is a measure of electric potential difference between two electrical points. O It's an electrical cliche. The other point could be negative or positive. None of the above.Problem 5 Find the equivalent inductance Leg for the network shown below. 72 mH oooo Leg 49 mH elle elle 313 mH elle 64 mH elle 80 mH
- The complex volt amperes in a series circuit are (4300- j2500) and the current is (25 + j43.3)A.Find the applied voltage.calculate the magnitude of the current through the j3.3k ohm inductor. jl k2 1.2 k2 -j4.7 k2 j2.2 k2 8j3.3 k2 20 V/15° 50 V/60° Figure 24-27 ll llAn inductor and a 470 ohm resistor are connected in series with a function generator. The current is 53.7mA RMS 8kHz. The reactive power is 2.32 var. Find the value of the inductance.