Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN: 9780470458365
Author: Erwin Kreyszig
Publisher: Wiley, John & Sons, Incorporated
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5.7.6

**Problem Statement:**

Find the double integral \(\iint_R (2x + 3y) \, dA\) where \(R\) is the parallelogram with vertices \((0,0)\), \((-1,-4)\), \((-3,-2)\), and \((-4,-6)\).

Use the transformation \(x = -u - 3v\), \(y = -4u - 2v\).

**Explanation:**

The task is to calculate the integral of the function \(2x + 3y\) over the region \(R\), which is defined as a parallelogram in the \(xy\)-plane. The region's vertices are given as \((0,0)\), \((-1,-4)\), \((-3,-2)\), and \((-4,-6)\).

To solve this problem, we employ a change of variables defined by the transformation:
- \(x = -u - 3v\)
- \(y = -4u - 2v\)

This transformation allows us to potentially simplify the computation of the integral by mapping the parallelogram \(R\) into a new region in the \(uv\)-plane. The task would typically involve finding the Jacobian of the transformation to correctly handle the area differential when changing from \(dA\) to \(dudv\).
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Transcribed Image Text:**Problem Statement:** Find the double integral \(\iint_R (2x + 3y) \, dA\) where \(R\) is the parallelogram with vertices \((0,0)\), \((-1,-4)\), \((-3,-2)\), and \((-4,-6)\). Use the transformation \(x = -u - 3v\), \(y = -4u - 2v\). **Explanation:** The task is to calculate the integral of the function \(2x + 3y\) over the region \(R\), which is defined as a parallelogram in the \(xy\)-plane. The region's vertices are given as \((0,0)\), \((-1,-4)\), \((-3,-2)\), and \((-4,-6)\). To solve this problem, we employ a change of variables defined by the transformation: - \(x = -u - 3v\) - \(y = -4u - 2v\) This transformation allows us to potentially simplify the computation of the integral by mapping the parallelogram \(R\) into a new region in the \(uv\)-plane. The task would typically involve finding the Jacobian of the transformation to correctly handle the area differential when changing from \(dA\) to \(dudv\).
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