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Transcribed Image Text:FINAL VELOCITY FROM EXPERIMENTAL DATA (LARGEST VELOCITY)
Vexperimental =
THEORETICAL VALUE OF FINAL VELOCITY.
h = Yfinal - Vinitial =
|vf - Vexperimental |
Vf
Vf = √2gh =
PERCENT DIFFERENCE
Percent difference
=
X 100% =
Transcribed Image Text:File
Formulas Data
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Chart 1
x ✓
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1
y(cm)
h (m) v (m/s)
y (m)
7.85 0.0785
2
0.03
0.00
K (J)
0.0000
0.0031
U (1)
0.0850
0.0817
E (J)
0.0850
0.0848
3
7.96 0.0796
0.03
0.14
4
8.88 0.0888
0.02
1.30
0.2519 0.0547
0.3065
5
8.16 0.0816
0.03
1.01
0.1543 0.0759
0.2301
6
8.78 0.0878
0.02
0.87
0.1144 0.0576 0.1720
7
8.57 0.0857
0.02
0.30
0.0131 0.0638 0.0769
8
8.73 0.0873
0.02
0.23
0.0076 0.0591 0.0667
9
9.4 0.0940
0.01
0.93
10
9.55 0.0955
11
0.01
9.86 0.0986 0.01
10.48 0.1048 0.00
10.74 0.1074 0.00
0.1299 0.0394 0.1693
0.21 0.0067 0.0350 0.0417
0.43 0.0278 0.0259 0.0537
0.86 0.1112 0.0076 0.1189
0.36 0.0196 0.0000 0.0196
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Conservation of Energy
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Home Insert Page Layout
fxx
A
t (s)
0.07029
0.078
0.0851
0.0922
0.0993
0.1064
0.1135
0.1207
0.1278
0.135
0.1422
0.1494
Chart Design
O
final y (m)
mass (kg)
Format
K
0.1074
0.3
Energy (J)
M
N
O
P
R
Q
For your data set, enter the final 'y' value in meters
Mass just needs to be approximate.
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Energy vs. Time - Jayell Johnson
0.3500
0.3000
0.2500
€ 0.2000
--Kinetic Energy
-Potential Energy
0.1500
-Total Energy
y = -1.5285x+0.2869
0.1000
-Linear Fit Total Energy
0.0500
0.0000
0
0.02
0.04
0.06
0.1
0.12
0.14
0.16
0.08
Time (s)
Conservation of Energy
An object with a known mass m (kg) is dropped from an initial height h (m) from ground level. Paste your data from Module
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