Fin the indicated area under the standard normal curve. Between z= 0 and z= 0.71   The area between z=0 and z=0.71 under the standar normal curve is =  (Round to four decimal places as needed).

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Find the indicated area under the standard normal curve. To the left of z = -2.92 and to the right of z = 2.92 Dick here to view page 1 of the standard normal table Click here to view page 2 of the standard normal table

Find the area of the indicated region under the standard normal curve. Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. The area between z = - 1.1 and z = 1.4 under the standard normal curve is (Round to four decimal places as needed.)

Determine the area under the standard normal curve that lies to the left of (a) Z= -0.28, (b) Z = -0.93, (c) Z= -0.73, and (d) Z= -0.43. Click the icon to view a table of areas under the normal curve. (a) The area to the left of Z= -0.28 is ound to four decimal places as needed.) 1- O E 'G 9 DELL 20

Find the indicated area under the standard normal curve. Between z= - 1.37 and z = 1.37 Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table, The area between z= - 1.37 and z =1.37 under the standard normal curve is (Round to four decimal places as needed.)

Find the indicated area under the standard normal curve. Between z= - 2.56 and z = 2.56 Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. ..... The area between z= - 2.56 and z = 2.56 under the standard normal curve is (Round to four decimal places as needed.)

Sketch the area under the standard normal curve over the indicated interval and find the specified area. (Round your answer to four decimal places.) The area between  z = 1.40  and z = 2.16 is  .

Sketch the area under the standard normal curve over the indicated interval and find the specified area. (Enter a number. Round your answer to four decimal places.) The area between z = 0.34 and z = 1.92 is .