Fill in the missing particle in each nuclear equation. At + He 217 a. b. 24Pu Na d. se + 241 5Am + Ne + 75 C 11 10

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Fill in the missing particle in each nuclear equation.
At + He
217
a.
b. 24Pu
Na
d. se +
241
5Am +
Ne +
75
C 11
10
Transcribed Image Text:Fill in the missing particle in each nuclear equation. At + He 217 a. b. 24Pu Na d. se + 241 5Am + Ne + 75 C 11 10
Expert Solution
Step 1

For this question we will use the concept of  mass no and atomic no.

we know that, 

i)the sum of atomic no of reactant = sum of atomic no of product

ii)the sum of mass no of reactant = sum of mass no of product

 

Part a)

for given nuclear reactionatomic no reactant particle= atomic no of At +atomic no of He                                        =85 +2                                        =87also,mass no reactant particle= mass no of At +mass no of He                                       =217 + 4                                       =221so, the element with atomic no 87 and mass no 221 is Franciumtherefore the missing particle is  F87221r ( Francium) 

The complete reaction is F87221r A85217t +H24e

 

For part b)

for given nuclear decay reaction of Puthe atomic no increases by 1the mass no remain unchangedtherefore it is β- decay. Because during β- decay the atomic no remain increases by 1 and mass no remain sameso, the missing particle is  β- ( e- -10)particle.

The complete reaction is P94241u A95241m +e--10  +ν

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