Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN: 9780470458365
Author: Erwin Kreyszig
Publisher: Wiley, John & Sons, Incorporated
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**Mathematical Induction Proof Explanation**

This proof demonstrates that the sequence defined by the recurrence relation:

\[ f_k = f_{k-1} + 2^k \; \text{for each integer} \; k \geq 2 \]

with the initial condition:

\[ f_1 = 1 \]

satisfies the formula:

\[ f_n = 2^n + 1 - 3 \; \text{for every integer} \; n \geq 1. \]

**Proof (by mathematical induction):**

*Base Case: Show that \( P(1) \) is true:*

- The left-hand side of \( P(1) \) is \( 2^2 - 3 \), which equals \( 1 \).
- The right-hand side of \( P(1) \) is \( 1 \).
- Since both sides equal each other, \( P(1) \) is true.

*Inductive Step: Show that for each integer \( k \geq 1 \), if \( P(k) \) is true, then \( P(k + 1) \) is true:*

- Assume \( P(k) \) is true, i.e., suppose \( f_k = 2^k + 1 - 3 \).
  
  By the recurrence relation:
  
  \[ f_k = f_{k-1} + 2^k \; \text{with initial condition} \; f_1 = 1. \]

*(This assumption is the inductive hypothesis.)*

- We must show \( P(k + 1) \) is true. Specifically, we need to show:

  \[ f_{k+1} = 2^{k+1} + 1 - 3. \]

- The left-hand side of \( P(k + 1) \) is calculated as follows:

  \[
  \begin{align*}
  f_{k+1} &= f_k + 2^{k+1} \quad \text{(by definition of \( f_k \))} \\
  &= (2^k + 1 - 3) + 2^{k+1} \quad \text{(by inductive hypothesis)} \\
  &= 2 \cdot 2^k + 1 - 3 \quad \text
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Transcribed Image Text:**Mathematical Induction Proof Explanation** This proof demonstrates that the sequence defined by the recurrence relation: \[ f_k = f_{k-1} + 2^k \; \text{for each integer} \; k \geq 2 \] with the initial condition: \[ f_1 = 1 \] satisfies the formula: \[ f_n = 2^n + 1 - 3 \; \text{for every integer} \; n \geq 1. \] **Proof (by mathematical induction):** *Base Case: Show that \( P(1) \) is true:* - The left-hand side of \( P(1) \) is \( 2^2 - 3 \), which equals \( 1 \). - The right-hand side of \( P(1) \) is \( 1 \). - Since both sides equal each other, \( P(1) \) is true. *Inductive Step: Show that for each integer \( k \geq 1 \), if \( P(k) \) is true, then \( P(k + 1) \) is true:* - Assume \( P(k) \) is true, i.e., suppose \( f_k = 2^k + 1 - 3 \). By the recurrence relation: \[ f_k = f_{k-1} + 2^k \; \text{with initial condition} \; f_1 = 1. \] *(This assumption is the inductive hypothesis.)* - We must show \( P(k + 1) \) is true. Specifically, we need to show: \[ f_{k+1} = 2^{k+1} + 1 - 3. \] - The left-hand side of \( P(k + 1) \) is calculated as follows: \[ \begin{align*} f_{k+1} &= f_k + 2^{k+1} \quad \text{(by definition of \( f_k \))} \\ &= (2^k + 1 - 3) + 2^{k+1} \quad \text{(by inductive hypothesis)} \\ &= 2 \cdot 2^k + 1 - 3 \quad \text
If a bank pays interest at a rate of \( i \) compounded \( m \) times a year, then the amount of money \( P_k \) at the end of \( k \) time periods (where one time period = \( 1/m \)th of a year) satisfies the recurrence relation:

\[
P_k = \left( 1 + \frac{i}{m} \right) P_{k-1}
\]

with initial condition \( P_0 = \) the initial amount deposited. Find an explicit formula for \( P_n \).

The given recurrence relation defines ___ with constant ____, which is _____. Therefore, \( P_n = \) _____ for every integer \( n \geq 0 \).

(Note: The blanks in the text are intended for user interaction to select or fill in values based on the context and equation provided.)
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Transcribed Image Text:If a bank pays interest at a rate of \( i \) compounded \( m \) times a year, then the amount of money \( P_k \) at the end of \( k \) time periods (where one time period = \( 1/m \)th of a year) satisfies the recurrence relation: \[ P_k = \left( 1 + \frac{i}{m} \right) P_{k-1} \] with initial condition \( P_0 = \) the initial amount deposited. Find an explicit formula for \( P_n \). The given recurrence relation defines ___ with constant ____, which is _____. Therefore, \( P_n = \) _____ for every integer \( n \geq 0 \). (Note: The blanks in the text are intended for user interaction to select or fill in values based on the context and equation provided.)
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