Figure 4 shows the reflection of two rays of radiation from consecutive planes with spacing d, where θ is the angle of incidence as shown. Explain why constructive interference occurs if the following condition is obeyed: 2d sin θ = λ, where λ is the wavelength of the radiation. d) Table 1 shows a set of measured values for angles 2θ at which peaks in scattered radiation are observed, where λ = 1.4 A is the wavelength of the radiation.  (i) Fill in the second column of the table, showing squared plane spacings (in units of A˚2) corresponding to the measured deflection angles. (ii) Fill in the third column, where d0 is the plane spacing corresponding to the first entry in column 2. (iii) Find an integer N in the final column of the table, that makes all entries an integer.

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a)  Figure 4 shows the reflection of two rays of radiation from consecutive planes with spacing
d, where θ is the angle of incidence as shown. Explain why constructive interference occurs
if the following condition is obeyed:
2d sin θ = λ,
where λ is the wavelength of the radiation.

d) Table 1 shows a set of measured values for angles 2θ at which peaks in scattered radiation
are observed, where λ = 1.4 A is the wavelength of the radiation. 
(i) Fill in the second column of the table, showing squared plane spacings (in units of A˚2)
corresponding to the measured deflection angles.
(ii) Fill in the third column, where d0 is the plane spacing corresponding to the first entry
in column 2.
(iii) Find an integer N in the final column of the table, that makes all entries an integer. 

8
20
2
d
Figure 4: Reflection of radiation from two consecutive planes.
20/⁰ ď² = (A/2 sin 0)² | ²/ď² | NŒ²/ď²
34.733
40.322
58.342
69.716
73.305
Table 1: Diffraction analysis for titanium carbide.
Transcribed Image Text:8 20 2 d Figure 4: Reflection of radiation from two consecutive planes. 20/⁰ ď² = (A/2 sin 0)² | ²/ď² | NŒ²/ď² 34.733 40.322 58.342 69.716 73.305 Table 1: Diffraction analysis for titanium carbide.
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