College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Expert Solution
arrow_forward
Step 1
When the electron enters the magnetic field, the magnetic force is equal to the centripetal force.
Apply the work-energy theorem and substitute the required expression for the velocity to obtain the expression for the potential difference.
Step by stepSolved in 3 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- (Figure 1) shows a mass spectrometer, an analytical instrument used to identify the various molecules in a sample by measuring their charge-to- mass ratio q/m. The sample is ionized, the positive ions are accelerated (starting from rest) through a potential difference AV, and they then enter a region of uniform magnetic field. The field bends the ions into circular trajectories, but after just half a circle they either strike the wall or pass through a small opening to a detector. As the accelerating voltage is slowly increased, different ions reach the detector and are measured. Consider a mass spectrometer with a 200.00 mT magnetic field and an 8.0000 cm spacing between the entrance and exit holes. igure + AV d Detector Part A To five significant figures, what accelerating potential difference AV is required to detect the ion O,? The masses of the atoms are shown in the table; the mass of the missing electron is less than 0.001 u and is not relevant at this level of precision. Use…arrow_forwardMedical cyclotrons need efficient sources of protons to inject into their center. In one kind of ion source, hydrogen atoms (i.e., protons with one orbiting electron) are fed into a chamber where there is a strong magnetic field. Electrons in this chamber are trapped in tight orbits, which greatly increases the chance that they will collide with a hydrogen atom and ionize it. One such source uses a magnetic field of 50 mT, and the electrons’ kinetic energy is 2.0 eV. If the electrons travel in a plane perpendicular to the field, what is the radius of their orbits?arrow_forwardA singularly-charged ion (i.e. a neutral atom which has gained one electron) with kinetic energy of 7x10−15 J follows a circular path of radius 0.6m when placed in a magnetic field of 0.5T. (Note that the charge of an electron is e = 1.6 x 10−19 C.) a) Using the fact that the ion is going in a circular motion in a magnetic field, what is the ion’s momentum (in kg.m/s)? b) What is the ion’s speed (in m/s)? c) What is the ion’s mass (in kg)? d) An electric field is added to the experiment and adjusted so that the ion passes through without any deflection. What is the magnitude of this electric field (in T)?arrow_forward
- The earth's magnetic field can affect the electron beam in an oscilloscope or a television tube. An electron that has been accelerated through a potential difference of 5.03 104 V has a horizontal initial velocity, directed north. Find the magnetic force on the electron when the earth's field has a horizontal component of 0.250 G and dips 60.0° below the horizontal (values typical in California). Magnitude ______ Direction _______arrow_forwardIn a mass spectrometer, the mass of a particle is determined by it's circular path in a magnetic field of value B= 1T. Here, we consider a particle of charge q=te = 1.6 x 10"C that is accelerated across a potential difference AV :- 500 Volts. As shown, this particle enters a chamber with a uniform magnetic field. The particle makes a circular path and strikes the detector a distance I=8 Cm from where it entered the chamber. Part A Determine the mass of the particle. Vo AEO m 3= kgarrow_forwardThe deuterons, the nuclei of heavy hydrogen, are accelerated and injected into a region with constant magnetic field (a cyclotron). Determine the cyclotron frequency of the particles, if the strength of the magnetic field in the cyclotron is 1.35 T and the mass of deuteron is 3.3 × 10-27 kg. The cyclotron frequency, f = Determine the cyclotron radius for the particles, which enters the cyclotron with a kinetic energy of 25 MeV. The radius, R = Question Help: Units Select an answer ✓ Units Select an answer Message instructor Post to forumarrow_forward
- An electron in the beam of a cathod-ray tube is accelerated by a potential difference of 2.14 kV . Then it passes through a region of transverse magnetic field, where it moves in a circular arc with a radius of 0.190 m . What is the magnitude of the field?arrow_forwardWrite down an expression for the force experienced by an electron moving with a velocity, v, in a magnetic field B. By equating this expression to the force required to cause electrons to follow a circular path of radius, r, derive an expression for the ratio, (?⁄?) for an electron in terms of the magnetic field strength, the radius of the circular path and the accelerating potential, V.arrow_forwardStarting from rest, an electron is accelerated through a region between two oppositely charged plates, as shown in Figure 1. The distance between the plates is 10 cm and the magnitude of the potential difference between them is 100 V. Immediately after exiting the region with the uniform electric field, the electron enters a region with a uniform magnetic field of 0.85 T, directed into the page. (a) Calculate the magnitude of the electric force on the electron. (b) Calculate the work done by the electric force on the electron. (c) Determine the electron's speed when it enters the magnetic field. (d) Determine the magnitude and direction of the magnetic force on the electron when it enters the magnetic field. (e) Suppose that the experiment was repeated with the locations of the positive and negative plates switched, and the electron was replaced with a proton, but nothing else was changed. Calculate R,/R., the ratio of the radius of the proton's path in the magnetic field (R,) to that…arrow_forward
- An electron moves at a speed of 810 m/s perpendicular to the direction of a uniform magnetic field of 0.4 T. What is the radius of the electron's circular orbit in units of nanometers (1 m = 10° nm)? (in units of nanometers)arrow_forwardA proton moves in a circular motion perpendicular to a uniform magnetic field of 0.75 T. Find the time for the proton to make one complete circular orbit.arrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
University Physics (14th Edition)
Physics
ISBN:9780133969290
Author:Hugh D. Young, Roger A. Freedman
Publisher:PEARSON
Introduction To Quantum Mechanics
Physics
ISBN:9781107189638
Author:Griffiths, David J., Schroeter, Darrell F.
Publisher:Cambridge University Press
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:9780321820464
Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:Addison-Wesley
College Physics: A Strategic Approach (4th Editio...
Physics
ISBN:9780134609034
Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:PEARSON