College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- Solve the followingarrow_forwardNot all "springs" are described well by Hooke's law; Hooke's law is a "first order" approximation. Say that a spring exerts a force F that is the following function of displacement: x=xi Please see the image below for the rest of the problem and answer choices.arrow_forwardFroghoppers may be the insect jumping champs. These 6-mm-long bugs can spring 70 cm into the air, about the same distance as the flea. But the froghopper is 60 times more massive than a 12-mg flea. The froghopper pushes off for about 4 mm Part A Determine the average force that the froghopper exerts on the surface. Express your answer with the appropriate units.arrow_forward
- You are asked to design spring bumpers for the walls of a parking garage. A freely rolling 1300 kgkg car moving at 0.67 m/sm/s is to compress the spring no more than 0.066 mm before stopping. Part A What should be the force constant of the spring? Assume that the spring has negligible mass. Express your answer in newtons per meter.arrow_forwardhelparrow_forwarda) Given the following ideal Atwood machine in an elevator accelerating down at ae = 4.9 m/s2, with m1 = 10 gram (two nickels) and m2 = 5 gram (one nickel) as shown, what is the tension T in the string in millinewton (mN)? (Hint: the upward arrow on ae is correct and just means use "positive is up" conventions for the elevator itself, so here we have ae = -4.9 m/s2 to be put into Einstein's rule that we discussed.) b) Exact same Atwood machine as the previous problem (two nickels and a nickel in an elevator accelerating down at 4.9 m/s2), but now how much time (s) does it take m1, starting from rest, to fall 25 cm relative to the inside of the elevator? I labeled it a and b because they are connected to each other. Please help, thanks!arrow_forward
- Question 1arrow_forwardMove over Jeff Bezos, this invention is about to make you the richest person in the world. You have just invented the OyOy (that's YoYo spelled backwards). It is the very latest in home safety and so easy to use! If your building is on fire, simply reach out and grab the cord on the Oyoy and you will be lowered safely toward the ground at a low velocity. The OyOy has a total mass M = 106.0 kg and is shaped like a cylinder of radius R = 0.835 meters. The secret to the operation of the OyOy is its patented shaft whose radius is only r = 0.0830 meters. The cord is wound around the small shaft and this is the secret to your low velocity. Outer Radius = R Spindle Radius = r Mass = M The FORMULA for the moment of Inertia: I = V(y=0)=? We will use the approximation that the shaft is of negligible mass compared to the total. This means that you can treat the entire OyOy as though it is a solid cylinder with mass M and radius R. Imagine that a customer of mass m = 77.5 kg is using the Oyoy and…arrow_forwardPlease Asaparrow_forward
- A 2.5 kg object is moving to the right with a speed of 1.0 m/s when it experiences the force shown in (Figure 1). Figure Fx (N) 12- Io 0.50 s 0 -12- t (s) 1 of 1 Part A What are the object's speed and direction after the force ends? Express your answer with the appropriate units. Enter positive value if the speed is directed to the right and negative value if the speed is directed to the left. VI = Submit μA Value Provide Feedback Request Answer Units ? Activate Windo Go to Settings to actarrow_forwardⒸ Macmillan Learning A block of mass m = 6.23 kg is attached to a spring that is resting on a horizontal, frictionless table. The block is pushed into the spring, compressing it by 5.00 m, and is then released from rest. The spring begins to push the block back toward the equilibrium position at x = 0 m. The graph shows the component of the force (in newtons) exerted by the spring on the block versus the position of the block (in meters) relative to equilibrium. Use the graph to answer the questions. How much work W is done by the spring in pushing the block from its initial position at x = -5.00 m to x = 2.20 m? W = V = -59.04 Incorrect What is the speed of the block when t reaches x 2.20 m? 2.41 Incorrect Umax = What is the maximum speed max of the block? 3.63 J Incorrect m/s m/s 6 5. 4. 3. 2 ↓ L₁ -3. -4. -5. -6. F (N) x(m) $arrow_forwardPlease answer the question correctlyarrow_forward
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