FIGURE 1 FIGURE 1 shows a horizontal human arm lifting a dumbbell. The forearm is in equilibrium under the action of the weight W of the dumbbell, the tension T in the tendon connected to the biceps muscle, and the force E exerted on the forearm itself. (For clarity, the point A where the tendon is attached is drawn farther from the elbow than its actual position) Given the weight of the forearm is 20 N and the mass of the dumbbell is 20 kg. The angle between the tension force and the horizontal, 0 is 80°. The length of the horizontal arm is 0.30 m. The horizontal distance between elbow pivot and point A is 0.050 m. Find T and the vector E and draw free body diagram for this case.

A bag of cement whose weight is Eg hangs in equilibrium from three wires as shown in Figure. Two of the wires make angles 01 and 02 with the horizontal. Assuming the system is in equilibrium. What is the tension in the left-hand wire? Fg cos 02 a) T1 sin(8,+82) Fg sin 02 sin(e,+82) b) T1 2Fg cos 02 c) T1 sin(e,+02) 2Fg sin 82 d) T = cos(e,+02) 3Fg sin 02 e) T1 cos(e,+02) CEMENT

A 28.9 kg mass (m) is suspended by the cable assembly as shown in the figure. The cables have no mass of their own. The cable to the left (7₁) of the mass makes an angle of 0.00° with the horizontal, and the cable to the right (T2) makes an angle (02) of 32.2°. If the mass is at rest, what is the tension in each of the cables, T₁ and T2? The acceleration due to gravity is g = 9.81 m/s². T₁ = T₂ = N N T₁ m T₂ 0₂

A sailor is being rescued using a boatswain’s chair that is suspended from a pulley that can roll freely on the support cable ACB and is pulled at a constant speed by cable CD . Knowing that a = 30° and β = 10° and that the combined weight of the boatswain’s chair and the sailor is 200 lb, determine the tension (a) in the support cable ACB, (b) in the traction cable CD.

A 20.4 kg mass (m) is suspended by the cable assembly as shown in the figure. The cables have no mass of their own. The cable to the left (T) of the mass makes an angle of 0.00° with the horizontal, and the cable to the right (T2) makes an angle (02) of 30.1°. If the mass is at rest, what is the tension in each of the cables, T and T2? The acceleration due to gravity T, T, is g = 9.81 m/s². N T1 = m N T2 =

The block shown in (Figure 1) has a mass of m = 75 kg, a height H = 1.1 m, and width L = 1.6 m. It is resting on a ramp that makes an angle 0 = 34° with the horizontal. A force P is applied parallel to the surface of the ramp at the top of the block. What is the maximum force that can be applied without causing the block to move? The coefficient of static friction is μs = 0.42, and the center of mass of the block is at the center of the rectangle. What is the maximum magnitude of P that can be applied before tipping would occur, assuming the block does not slip? Express your answer to three significant figures with appropriate units. Ptip = 649 N Submit Previous Answers Correct Figure W H F x 2 of 2 Part F What is the maximum magnitude of P that does not cause motion of the block? Express your answer to three significant figures with appropriate units. ☐ μÅ Pmax = |667.611 N Submit Previous Answers Request Answer × Incorrect; Try Again; 5 attempts remaining Provide Feedback ? Review…

In the figure, a 799 kg construction bucket is suspended by a cable A that is attached at O to two other cables B and C, making angles 0₁ = 55.0° and 0₂ = 66.0° with the horizontal. Find the tensions in (a) cable A, (b) cable B, and (c) cable C. (Hint: To avoid solving two equations in two unknowns, position the axes as shown in the figure.) (a) Number i (b) Number (c) Number i Units Units Units B A C 09 >

A 30.6 kg mass (m) is suspended by the cable assembly as shown in the figure. The cables have no mass of their own. The cable to the left (T|) of the mass makes an angle of 0.00° with the horizontal, and the cable to the right (T2) makes an angle (02) of 36.4°. If the mass is at rest, what is the tension in T each of the cables, T¡ and T,? The acceleration due to gravity is g = 9.81 m/s². T = N m T2 = N

A 150.8-N bird feeder is supported by three cables as shown in the figure below. Find the tension in each cable. A bird feeder is suspended from a vertical cable. The top left cable of the cable is tied to two other cables. The left and right cables go up and to the left and up and to the right, respectively, from the connection point to a horizontal bar. The left cable makes an angle of 60° with the bar. The right cable makes an angle of 30° with the bar. right cable bottom cable N 60° 30° Bird food