Fig 1. Parallel Plate Capacitor with two dielectric materials. The area of the capacitor is 0.24m². The top plate (electrode) is positively charged. in each of the dielectric Question 1: Use Gauss law to find an expression for the electric field materials. Put the value of electric field in dielectric 2 if there is a charge of Q=2.3 μC on the plates in your answer table.

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.