Fifty kilograms of toxic material is spilled uniformly across a canal. The canal is trapezoidal with a bottom width of 3 m, side slopes of 2.5:1 (H : V ), and a depth of flow of 1.7 m. The discharge in the canal is 16 m3/s, and the longitudinal diffusion coefficient is 7 m2/s. Cross sectional area = A = by+my^2 = (3m)*(1.7m)+(2.5)*(2.89 m^2) = 12.325 m^2 What length of canal is contaminated 2 hours after the spill?
Fifty kilograms of toxic material is spilled uniformly across a canal. The canal is trapezoidal with a bottom width of 3 m, side slopes of 2.5:1 (H : V ), and a depth of flow of 1.7 m. The discharge in the canal is 16 m3/s, and the longitudinal diffusion coefficient is 7 m2/s. Cross sectional area = A = by+my^2 = (3m)*(1.7m)+(2.5)*(2.89 m^2) = 12.325 m^2 What length of canal is contaminated 2 hours after the spill?
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Fifty kilograms of toxic material is spilled uniformly across a canal. The canal is trapezoidal with a bottom width of 3 m, side slopes of 2.5:1 (H : V ), and a depth of flow of 1.7 m. The discharge in the canal is 16 m3/s, and the longitudinal diffusion coefficient is 7 m2/s.
Cross sectional area = A = by+my^2 = (3m)*(1.7m)+(2.5)*(2.89 m^2) = 12.325 m^2
What length of canal is contaminated 2 hours after the spill?
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