fgets() function removes the vulnerability of gets() function by introducing a limit to string length. Question 11 options: True False
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fgets() function removes the vulnerability of gets() function by introducing a limit to string length.
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- Topics: User-defined functions, list, string, docstringProblem Statement: This program finds the unique letters from a given string and printsthe unique letters and their count. For example: word ‘LITTLE’ has ‘L’, ‘I’, ‘T’, ‘E’ are theunique letters.Lab Scenario:The program repeats until hits ‘n’. The program takes a user input of a string. The programfinds the unique letters in the string, add them in a list and displays the list and their count.Consider the following important points:1) You need to design a user-defined function named count_unique_letters whichtakes user word as parameter and returns the list of unique letters calledunique_letters in the given word.a. Hint: Iterate over each letter in user word, check if the letter is in the list, if notadd it to the list, otherwise continue to the next letter. A ‘in’ keyword can helpto determine if a character in the unique_letters list.b. You need to write a simple docstring for this function.2) Your program must have a main()…Complete the check_strings_same_start(word1, word2) function which is passed two string parameters. The function returns True if the two parameter strings start with the same character and only one (not both) of the parameter strings has an even number of characters (including any space characters), otherwise the function returns False. For example: Test Result result = check_strings_same_start("blue", "bag") True print(result) print(check_strings_same_start("babyproofing", "baby")) False print(check_strings_same_start("check", "fact")) False• get_tokens_from_equation(line): Takes one string as input that contains any combination of digits from 0-9 and the following mathematical symbols: + - x / = ^ (O The string does not have to correspond to a valid mathematical equation. For example, '4-3=0' and '4xx5=(8' could be valid inputs to this function. The function will translate the string into a list of tokens. A token is a single non-negative number (of any length) or a single mathematical symbol. Numbers should be added to the list as integers, and symbols as strings. The tokens in the list should be in the same order as the numbers/symbols appear in the string. For example, given the string '52-2=50', the function should return the list [52, '-', 50]. >>> get_tokens_from_equation('4=3') [4, '=', 3] >>> get_tokens_from_equation('6-5=15^4/2') [6, '-', 5, '=', 15, '^', 4, '/', 2] >>> get_tokens_from_equation('288/24x6=18x13x8') [288, '/', 24, 'x', 6, '=', 18, 'x', 13, 'x', 8]
- get_nth_word_from_string(s, n): This function takes a string s and a non-negative integer n as input. The string s may contain substrings of text separated by commas. The function should return the n’th comma-separated substring. We will start counting at 0, so if n=0, then the first substring should be returned (i.e., everything before the first comma, if there is such a comma); if n=1, then the second substring should be returned (i.e., everything between the first comma and second comma, if there is such a comma); and so on. If there is no n’th substring in s, then the empty string should be returned. Note: You may use the string count method in this function. Note: If a space follows a comma, do not include the space as part of the substring to be returned.get_nth_word_from_string(s, n): This function takes a string s and a non-negative integer n as input. The string s may contain substrings of text separated by commas. The function should return the n’th comma-separated substring. We will start counting at 0, so if n=0, then the first substring should be returned (i.e., everything before the first comma, if there is such a comma); if n=1, then the second substring should be returned (i.e., everything between the first comma and second comma, if there is such a comma); and so on. If there is no n’th substring in s, then the empty string should be returned. Note: You may use the string count method in this function. Note: If a space follows a comma, do not include the space as part of the substring to be returned. >>> get_nth_word_from_string("dreary, pondered, weak, weary", 0) 'dreary'Inside this module, import random and blackout_utils, and define the following global variable, which you should use whenever appropriate: OPERATIONS = ['^', 'x', '/', '+', '-']For full marks, all the following functions must be part of this module: calculate(tokens): Takes one list of tokens as input corresponding to a mathematical equation. The function will evaluate both sides of the equality and return a list of three tokens: the result of the left-hand side (integer), the equals sign (string), and the result of the right-hand side (integer). The equation may contain any of the operations in the OPERATIONS list, as well as opening and closing parentheses. Your function should evaluate both sides of the equation while respecting order of operations (that is, parentheses, followed by exponentiation, then multiplication and division, and then addition and subtraction). Equations may have multiple sets of parentheses and nested parentheses. The contents of the inner-most nested…
- 3. Complete the function count_digits. This function takes one parameter - a string (s). It should return the number of digits in s. For example, if s is "25 or 6 to 4 is a song by Chicago" then count_digits should return 4. count_digits should not print the result- it should return it. Do not change anything outside count_digits. Save & Run Load History Show CodeLens 1 def count_digits(s): 2 ''Returns the number of digits in s''" 3 pass #Hint: make a string of digits to use #in checking whether each character #is a digit. And use the accumulator #pattern 4 6. 7 8. 9 user_string 10 num_digits 11 print("There are", num_digits, "digits in", user_string) input("Please enter a string: ") count_digits(user_string) 12function loginValidate () { var id = document.getElementById ('myid').value; var pass = document.getElementById('mypassword').value; if ((id == null : id alert ("ID and Pasword both must be filled out") : "") && (pass == null , pass == ")){ == return false: else if (id == null || id == "") { alert ("ID must be filled out "); return false; else if (pass == null || pass == "") { alert ("Password must be filled out "); return false;Implement the Function has_error Implement the function according to the specification. Use the test script testcurrency.py to aid your development before checking your answer below. CANNOT USE IF/CONDITIONAL STATEMENTS Instead, you should use what you know about boolean expressions def has_error(json):"""Returns True if the response to a currency query encountered an error. Given a JSON string provided by the web service, this function returns True if thequery failed and there is an error message. For example, if the json is '{"success":false,"src":"","dst":"","error":"Source currency code is invalid."}' then this function returns True (It does NOT return the error message'Source currency code is invalid'). On the other hand if the json is '{"success": true, "src": "2 United States Dollars", "dst": "1.772814 Euros", "error": ""}' then this function returns False. The web server does NOT specify the number of spaces after the colons. The JSON '{"success":true, "src":"2 United…
- The function count_contains_og in python takes a list of strings and returns how many strings in the list contain 'og' / 'OG' / 'oG' / 'Og' (check for 'og', ignoring case). Hint: Use the sequence membership operator in to help you check for 'og' in the individual strings. Create a lower-cased version of the string (lower), then use the in operator. For example: Test Result str_list = ['cat', 'dog', 'FROG', 'monkey'] print(count_contains_og(str_list)) 2 strlist = ["X", "x"] print(count_contains_og(strlist)) 0 list_of_one_og = ["Doggie"] print(count_contains_og(list_of_one_og)) 1Brussel's choice def brussels_choice_step(n, mink, maxk): This problem is adapted from another jovial video "The Brussel's Choice" of Numberphile (a site so British that you just know there has to be a Trevor and a Colin somewhere in there) whose first five minutes you should watch to get an idea of what is going on. This function should compute and return the list of all numbers that the positive integer n can be converted to by treating it as a string and replacing some substring m of its digits with the new substring of either 2*m or m/2, the latter substitution allowed only when m is even so that dividing it by two produces an integer. This function should return the list of numbers that can be produced from n in a single step. To keep the results more manageable, we also impose an additional constraint that the number of digits in the chosen substring m must be between mink and maxk, inclusive. The returned list must contain the numbers in ascending sorted order.Complete the rotate_text() function that takes 2 parameters, a string data and an integer n. If n is positive, then the function will shift all the characters in data forward by n positions, with characters at the end of the string being moved to the start of the string. If n is 0 then the text remains the same. For example: rotate_text('abcde', rotate_text('abcde', rotate_text('abcde', 1) would return the string 'eabcd' 3) would return the string 'cdeab' 5) would return the string 'abcde' rotate_text('abcde', 6) would return the string 'eabcd' ... and so on. If n is negative, then the function will shift the characters in data backward by n positions, with characters at the start of the string being moved to the end of the string. For example: rotate text('abcde', -1) would return the string 'bcdea'