[Falkner Section 11 Exercise 15(b) – modified] Let S and T be sets. Prove that S and T are disjoint (i.e., SnT = Ø) if and only if the following condition holds: (*) For all subsets A₁, A₂ C S and B₁, B₂ C T, if A₁ U B₁ = A₂ U B2, then A₁ = A2 and B₁ B2₂. =

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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1. [Falkner Section 11 Exercise 15(b) – modified] Let S and T be sets. Prove that
S and T are disjoint (i.e., SnT = Ø) if and only if the following condition holds:
(*)
For all subsets A₁, A₂ C S and B₁, B2 C T, if A₁ U B₁ = A₂ U B2,
then A₁
A2 and B₁ B₂.
Note: The condition (+) is equivalent to the statement that the function
=
=
ƒ: P(S) × P(T) → P(SŪT)
(A, B) → AUB
is injective. You proved on Homework 22 that this function is always surjective.
Transcribed Image Text:1. [Falkner Section 11 Exercise 15(b) – modified] Let S and T be sets. Prove that S and T are disjoint (i.e., SnT = Ø) if and only if the following condition holds: (*) For all subsets A₁, A₂ C S and B₁, B2 C T, if A₁ U B₁ = A₂ U B2, then A₁ A2 and B₁ B₂. Note: The condition (+) is equivalent to the statement that the function = = ƒ: P(S) × P(T) → P(SŪT) (A, B) → AUB is injective. You proved on Homework 22 that this function is always surjective.
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