F9-6. Locate the centroid z of the homogeneous solid formed by revolving the shaded area about the z axis.

Q: SOLVE the location of the Centroid from column ABC

A: Given data in question  Frame Point loads Span member lengths  Uniform columns   To find out…

Q: Euro copter 130 F-WGYP Model was remodeled by John McClane to be weaponized. He plans to integrate a…

A:

Q: AT

A:

Q: 1. Discuss the stability and determinacy of the beams shown (c) (d)

A:

Q: Locate the centroid of the wire shown.

A: Given: Required: Locate the centroid

Q: eta = 30 degree T = 6kN   Find the magnitude of the resultant forces acting on the eyebolt.

A: Rx=Tsinθ+8cos45Ry=Tcosθ-8sin45Rx=6sin(30)+8cos45Ry=6cos(30)-8sin45Rx=8.65685kNRy=-0.4607

Q: Find the point that extends the line from (-2,-7) to (2,-3) in the ratio -7/3.

A: This is the problem based on section formula with external division. Let P be that extended point.…

Q: B D

A: Given:- udl=4W working stresses=60MPain tension and 100MPa in compression I=75 x 10 6mm4 To find:- W

Q: 17 The two structural members, one of which is sion and the other in compression, exert t cated…

A: Solution: From the given figure Resultant force in the x directionRx=335+2cos 30°=1.8+1.732=3.53…

Q: 4m 20 KN 43 5 kN/m E = 200 GPa I = 2X 108 MMY

A: Using superposition theorem

Q: Solve using Mohr's circle. 9-23. The wood beam is subjected to a load of 12 kN. If a grain of wood…

A:

Q: A steel rod composed of two parts (AD and DB), which have different cross-sectional area, is fixed…

A:

Q: 20KN 3m RI R2

A: Apply equilibrium condition : ∑FX=0∑FY=0∑M=0

Q: 2. Compute the shearing stress in the pin at B for the member supported as show the given figure.…

A: Given- Diameter of Pin (d)=22 mm

Q: Compute the bar forces in the lettered bars of the truss shown. P Ja 45° 45°

A:

Q: 800 N•m y A 150 N 3 m 2.5 m 200 N -4 m 90 Ν Fig. P3.67

A:

Q: ) The x−coordinate of the centroid for this shape is located: To the left of the ?−y−axis…

A: In the given question figure

Q: A 5 m simple supported rectangular beam has a dimension of b = 150 mm and d = 350 mm is subject to a…

A: A beam which is free to move in horizontal direction and rests on two supports ( pin and roller) is…

Q: 85 KN 75 KN 100 KN F B 6 m 4 m A E G 4 m C 4 m 3 m

A: Step-1 find support reaction using equilibrium condition Step-2 cut the section and find the member…

Q: A pillar has a uniform section as indicated. It has a length 0.9 m, cross-sectional area 12.2 x 104…

A: Given data:- The length is 0.9m The cross-sectional area, A=12.2×10-4m2 In the second moment of…

Q: Find the the forces of the members about joint B

A:

Q: Question # 3: The built-up beam is fabricated from the three thin plates having a thickness 20 mm.…

A: Solution:

Q: %23

A:

Q: The neutral axis of the cross-section a beam is that axis at which the bending stress is A. infinity…

A:

Q: A22. Two C200 x 28 channèls are latticed together to form the section shown in E P-A22. Determine…

A:

Q: Determine static and external indeterminacy

A: static indeterminacy of Frame                                            3m +r - 3J Here…

Q: find the center of pressure of this shape

A: TO FIND :  CENTER OF PRESSURE

Q: 1-34. When the force P is applied to the plate, the velocity profile for a Newtonian fluid that is…

A:

Q: आहम

A: since the reactions at supports A and H are neither concurrent nor parallel. Therefore the the truss…

Q: 4. If the load P on the bean causes the end C to be displaced 10 mm downward, determine the normal…

A:

Q: force equal to -100 kN

A:

Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.