F2 = (2j – 4k} N Equivalent Systems Example 0.15 m • Replace the system with an equivalent resultant force and couple moment acting at point O. F1 = {6i – 3j – 10k} N 0.25 m FR = EF; FR = 6i – 3j – 10k + 2j – 4k 0.3 m {6i – lj – 14k} N i k |i j k + 0 -0.25 0.3 -10| |0 MRO 0.15 0.3 6. -3 {1.30i + 3.30j – 0.450k} N · m
F2 = (2j – 4k} N Equivalent Systems Example 0.15 m • Replace the system with an equivalent resultant force and couple moment acting at point O. F1 = {6i – 3j – 10k} N 0.25 m FR = EF; FR = 6i – 3j – 10k + 2j – 4k 0.3 m {6i – lj – 14k} N i k |i j k + 0 -0.25 0.3 -10| |0 MRO 0.15 0.3 6. -3 {1.30i + 3.30j – 0.450k} N · m
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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