F2 = (2j – 4k} N Equivalent Systems Example 0.15 m • Replace the system with an equivalent resultant force and couple moment acting at point O. F1 = {6i – 3j – 10k} N 0.25 m FR = EF; FR = 6i – 3j – 10k + 2j – 4k 0.3 m {6i – lj – 14k} N i k |i j k + 0 -0.25 0.3 -10| |0 MRO 0.15 0.3 6. -3 {1.30i + 3.30j – 0.450k} N · m

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Please show the stemps of how you solved this matrix and what its called.  I don't know how to get to the end result.

F2 = {2j – 4k} N
Equivalent Systems Example
0.15 m
F1 = {6i - 3j – 10k} N
• Replace the system with an equivalent resultant
force and couple moment acting at point O.
0.25 m
FR = EF; FR = 6i – 3j – 10k + 2j – 4k
%3D
0.3 m
{6i – lj – 14k} N
i
j
k
i
j
k
MR
0.15
0.3
+ 0
-0.25 0.3
6.
-3
-10
2
-4
{1.30i + 3.30j – 0.450k} N · m
Transcribed Image Text:F2 = {2j – 4k} N Equivalent Systems Example 0.15 m F1 = {6i - 3j – 10k} N • Replace the system with an equivalent resultant force and couple moment acting at point O. 0.25 m FR = EF; FR = 6i – 3j – 10k + 2j – 4k %3D 0.3 m {6i – lj – 14k} N i j k i j k MR 0.15 0.3 + 0 -0.25 0.3 6. -3 -10 2 -4 {1.30i + 3.30j – 0.450k} N · m
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