F2-16. Express the force as a Cartesian vector. F = 50 lb F2-16

Q1/ A-Given F1 -5.ON 30° N of E F2-7.0N 60° S of W and F3-10.0N 40° E of S. (a) Find the components of each vector. (b) Find the vector components of the resultant force . (c) Find the magnitude and direction of the resultant force.

Please help with: Determine the magnitude and location of the equivalent resultant of force.

F2-13. Determine its coordinate direction angles of the force. 45 -30° F = 75 lb F2-13 F2-14. Express the force as a Cartesian vector. F = 500 N 60° 60° F2-14 F2-15. Express the force as a Cartesian vector. F = 500 N 60 F2-15 F2-16. Express the force as a Cartesian vector. F-50 lb 1445 F2-16 F2-17. Express the force as a Cartesian vector. F = 750 N 45% F2-17 F2-18. Determine the resultant force acting on the hook. F₁ = 500 lb 30 45° F₂=800 lb F2-18 23