fonThe 4-lb rod AB hangs in the vertical position. A 2-lb block, sliding on a smooth horizontal surface with a velocity of (V)₁ = 12ft/s,strikes the rod at its end B. The coefficient of restitution between the block and the rod at B is e=0.6. Take the gravity g = 32.2 ft/s²there to search(Vb)iGAThe mass moment of inertia of the rod AB about an axis perpendicular to the screen passing through A isThe velocity of the block immediately after the collision isThe velocity of the point B on the rod after the collision is:# ft/s.O ft/s.BMENG300 Final Exa3 ftslug.ft².

Answered: Image /qna-images/answer/119b61f8-2a15-4705-8e59-620392400b09.jpg

f on The 4-lb rod AB hangs in the vertical position. A 2-lb block, sliding on a smooth horizontal surface with a velocity of (V)₁ = 12ft/s, strikes the rod at its end B. The coefficient of restitution between the block and the rod at B is e = 0.6. Take the gravity g = 32.2 ft/s² (Vb)i A # ft/s. O The mass moment of inertia of the rod AB about an axis perpendicular to the screen passing through A is The velocity of the block immediately after the collision is The velocity of the point B on the rod after the collision is: B ft/s. 3 ft = slug ft².

f on The 4-lb rod AB hangs in the vertical position. A 2-lb block, sliding on a smooth horizontal surface with a velocity of (V)₁ = 12ft/s, strikes the rod at its end B. The coefficient of restitution between the block and the rod at B is e = 0.6. Take the gravity g = 32.2 ft/s² (Vb)i A # ft/s. O The mass moment of inertia of the rod AB about an axis perpendicular to the screen passing through A is The velocity of the block immediately after the collision is The velocity of the point B on the rod after the collision is: B ft/s. 3 ft = slug ft².

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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